All categories

4 years ago

If the mass of an object increases, the force acting on it, such as gravitational force, also increases

Physics

1 answer:

strojnjashka [21]4 years ago

4 0

Its true because I just took the the test and it was right
I hope i helped you got it right

You might be interested in

Draw distance time grap for a body at rest

NARA [144]

It will be a straight horizontal line on the graph

4 0

4 years ago

If you mix 100 g of ice at 0 ∘c with 100 g of boiling water at 100 ∘c in a perfectly insulated container, the final stabilized t

loris [4]

The final stabilized temperature will be between 0 °C and 50 °C.

<h3>Calorimetry:</h3>

The enthalpy of fusion of ice is 334 J/g. The specific heat of water is 4.2 J/g.

To cool 100 g of water from 100 °C to 0 °C would require the removal of

4.2 x 100 x 100 = 42000 J.

To melt the ice would require the addition of

334 x 100 = 33400 J

∴ 42000 > 33400 thus you can melt all the ice and have some heat to spare, specifically 42000 - 33400 = 8600 J

Now use this to warm up 100+100 = 200 g of water at 0 °C

The final stabilized temperature;

8600 / (200 x 4.2) = 10.23 °C

Therefore, the final stabilized temperature is 10.23 °C

Learn more about Calorimetry here:

brainly.com/question/1989313

#SPJ4

4 0

2 years ago

Isla made ice by putting water in the freezer. Freezing is an example of (2 points)

SSSSS [86.1K]

Answer:

a physical change

6 0

3 years ago

Read 2 more answers

A thick steel sheet of area 100 in.2 is exposed to air near the ocean. After a one-year period it was found to experience a weig

vladimir1956 [14]

Answer:

Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.

Explanation:

The corrosion rate is the rate of material remove.The formula for calculating CPR or corrosion penetration rate is

$CPR=\frac{KW}{DAT}$

K= constant depends on the system of units used.

W= weight =485 g

D= density =7.9 g/cm³

A = exposed specimen area =100 in² =6.452 cm²

K=534 to give CPR in mpy

K=87.6 to give CPR in mm/yr

mpy

$CPR=\frac{KW}{DAT}$

$=\frac{534\times( 485g)\times( 10^3mg/g)}{(7.9g/cm^3) \times (100in^2)\times (24h/day)\times (365day/yr)\times 1yr}$

=37.4mpy

mm/yr

$CPR=\frac{KW}{DAT}$

$=\frac{87.6\times (485g)\times (10^3 mg/g)}{(7.9g/cm^3)\times (100in^2)\times(2.54cm/in)^2\times (24h/day)\times (365day/yr)\times 1yr}$

=0.952 mm/yr

Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.

3 0

4 years ago

A singly charged positive ion has a mass of 3.46 × 10−26 kg. After being accelerated through a potential difference of 215 V the

jasenka [17]

Answer:

1.8 cm

Explanation:

$m$ = mass of the singly charged positive ion = 3.46 x 10⁻²⁶ kg

$q$ = charge on the singly charged positive ion = 1.6 x 10⁻¹⁹ C

$\Delta V$ =Potential difference through which the ion is accelerated = 215 V

$v$ = Speed of the ion

Using conservation of energy

Kinetic energy gained by ion = Electric potential energy lost

$(0.5) m v^{2} = q \Delta V\\(0.5) (3.46\times10^{-26}) v^{2} = (1.6\times10^{-19}) (215)\\(1.73\times10^{-26}) v^{2} = 344\times10^{-19}\\v = 4.5\times10^{4} ms^{-1}$

$r$ = Radius of the path followed by ion

$B$ = Magnitude of magnetic field = 0.522 T

the magnetic force on the ion provides the necessary centripetal force, hence

$qvB = \frac{mv^{2} }{r} \\qB = \frac{mv}{r}\\r =\frac{mv}{qB}\\r =\frac{(3.46\times10^{-26})(4.5\times10^{4})}{(1.6\times10^{-19})(0.522)}\\r = 0.018 m \\r = 1.8 cm$

5 0

3 years ago