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Leya [2.2K]
3 years ago
7

Which statement about plant and animal cells is true?

Physics
1 answer:
Ivan3 years ago
4 0

Answer:

C. Both use mitochondria to release energy

Explanation:

Plant cells have a cell wall, a large vacuole and chloroplasts but animal cells do not.

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You read in a science magazine that on the Moon, the speed of a shell leaving the barrel of a modern tank is enough to put the s
olga_2 [115]

To solve this problem we will use the definition of the kinematic equations of centrifugal motion, using the constants of the gravitational acceleration of the moon and the radius of this star.

Centrifugal acceleration is determined by

a_c = \frac{v^2}{r}

Where,

v = Velocity

r = Radius

From the given data of the moon we know that gravity there is equivalent to

a = 1.62m/s

While the radius of the moon is given by

r = 1.74*10^6m

If we rearrange the function to find the speed we will have to

v = \sqrt{ar}

v = \sqrt{1.6(1.74*10^6)}

v = 1.7km/s

The speed for this to happen is 1.7km/s

3 0
3 years ago
1.<br> Kinetic energy is the energy of _____.
lorasvet [3.4K]

Explanation:

kinetic energy is energy that it possesses due to its motion.

7 0
4 years ago
All systems have what
Korvikt [17]
Number 3 is the naswer
6 0
4 years ago
Calculate the minimum average power output necessary for a person to run up a 12.0 m long hillside, which is inclined at 25.0° a
Viktor [21]

Answer:

Power, P = 924.15 watts

Explanation:

Given that,

Length of the ramp, l = 12 m

Mass of the person, m = 55.8 kg

Angle between the inclined plane and the horizontal, \theta=25^{\circ}

Time, t = 3 s

Let h is the height of the hill from the horizontal,

h=l\ sin\theta

h=12\times \ sin(25)

h = 5.07 m

Let P is the power output necessary for a person to run up long hill side as :

P=\dfrac{E}{t}

P=\dfrac{mgh}{t}

P=\dfrac{55.8\times 9.8\times 5.07}{3}

P = 924.15 watts

So, the minimum average power output necessary for a person to run up is 924.15 watts. Hence, this is the required solution.

3 0
3 years ago
How fast would a 0.25 kg football have to be traveling to have the same momentum as a 0.05 kg bullet traveling 500 m/s?
motikmotik
P=mv
0.25v=0.05*500
v=100 m/s
Pretty fast...
4 0
4 years ago
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