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patriot [66]
3 years ago
15

When randomly choosing two cards from a standard deck of cards without replacement, what is the probability of choosing a face c

ard and then an ace? (Remember: standard deck has 52 cards, with 4 aces and 12 face cards)
a)3/221
b)3/169
c)4/221
d)9/169
Mathematics
1 answer:
Radda [10]3 years ago
4 0
There are 12 face cards and 4 aces to choose from. For the first card, the probability of drawing a face is \dfrac{\binom{12}1}{\binom{52}1}=\dfrac{12}{52}. Then the probability of drawing an ace second is \dfrac{\binom41}{\binom{51}1}=\dfrac4{51}.

So the probability of drawing these two particular cards in the given order is

\dfrac{12}{52}\cdot\dfrac4{51}=\dfrac4{221}
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Can someone plz help me on this plz I beg u plz
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<h3>Answer:  25w+200 > 750</h3>

==========================================================

Explanation:

He starts off with 200 cards. Then he adds on 25w more cards for each week (w). Overall, he'll have 200+25w cards

We can think of it like this:

  • After 1 week, he adds on 25*1 = 25 cards
  • After 2 weeks, he adds on 25*2 = 50 cards total
  • After 3 weeks, he adds on 25*3 = 75 cards total
  • After 4 weeks, he adds on 25*4 = 100 cards total, and so on.
  • After w weeks, he adds on 25w cards total

So that's another way to see where the 25w comes from.

The expression 200+25w is the same as 25w+200. This is because we can add two numbers in any order.

------------

Since he wants to know when he'll have more than 750 cards, this means we set 25w+200 greater than 750.

That's how we get to the answer of 25w+200 > 750

Notice how there isn't a line under the inequality sign. We aren't using the "greater than or equal to" symbol here. We want to know when the cards gets over 750, but we don't want to know when it's equal to 750.

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