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ivolga24 [154]
2 years ago
14

The probability of getting disease X (event A) is 0.65, and the probability of getting disease Y (event B) is 0.76. The probabil

ity of getting both disease X and disease Y is 0.494. Are events A and B dependent or independent?
Mathematics
2 answers:
eimsori [14]2 years ago
4 0
I would say independent since the problem doesn't state any relation between disease X and disease Y. Also I beleive if it were dependent the probability of getting both wouldn't be .494 (which is .65 *.76). It would have to be probability of event A and event B, and then divided by probability of just B
BabaBlast [244]2 years ago
4 0

Answer:

The events A and B are independent

Step-by-step explanation:

The occurrence of disease X is not impacting the chances of occurrence of disease Y. Thus, these two events have no relation with each other.

The probability of getting both the disease X and disease Y when they both are considered as two independent events

= (0.65) ( 0.76)\\= 0.494

Thus , it can be said that the events A and B are independent

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1. The mechanics at Lincoln Automotive are reborning a 6 in deep cylinder to fit a new piston. The machine they are using increa
Firdavs [7]

Answer:

0.0239\frac{in^{3}}{min}

Step-by-step explanation:

In order to solve this problem, we must start by drawing a diagram of the cylinder. (See attached picture)

This diagram will help us visualize the problem better.

So we start by determining what data we already know:

Height=6in

Diameter=3.8in

Radius = 1.9 in (because the radius is half the length of the diameter)

The problem also states that the radius will increase on thousandth of an inch every 3 minutes. We can find the velocity at which the radius is increasing with this data:

r'=\frac{1/1000in}{3min}

which yields:

r'=\frac{1}{3000}\frac{in}{min}

with this information we can start solving the problem.

First, the problem wants us to know how fast the volume is increasing, so in order to find that we need to start with the volume formula for a cylinder, which is:

V=\pi r^{2}h

where V is the volumen, r is the radius, h is the height and π is a mathematical constant equal approximately to 3.1416.

Now, the height of the cylinder will not change at any time during the reborning, so we can directly substitute the provided height, so we get:

V=\pi r^{2}(6)

or

V=6 \pi r^{2}

We can now take the derivative to this formula so we get:

\frac{dV}{dt}=2(6)\pi r \frac{dr}{dt}

Which simplifies to:

\frac{dV}{dt}=12\pi r \frac{dr}{dt}

We can now substitute the data provided by the problem to get:

\frac{dV}{dt}=12\pi (1.9) (\frac{1}{3000})

which yields:

\frac{dV}{dt}=0.0239\frac{in^{3}}{min}

3 0
3 years ago
A cone is placed inside a cylinder, as shown below. They have the same height and diameter. About how much space is inside the c
nadezda [96]

The space is inside the cylinder but outside the cone is 200π cubic FT or 628.32 cubic FT.

<h3>What is a cone?</h3>

It is defined as the three-dimensional shape in which the base is a circular shape and if we go from circular base to top the diameter of the circle reduces and at the vertex, it becomes almost zero.

We know the volume of the cylinder is given:

\rm V = \pi r^2 h

r = 10/2 = 5 FT

h = 12 FT

\rm V = \pi (5)^2 \times 12

V = 300π cubic FT

Volume of the cone:

\rm v = \dfrac{\pi r^2 h}{3}

\rm v = \dfrac{\pi (5)^2 \times 12}{3}

v = 100π cubic FT

Space is inside the cylinder but outside the cone = 300π - 100π

= 200π cubic FT

= 628.32 cubic FT

Thus, the space is inside the cylinder but outside the cone is 200π cubic FT or 628.32 cubic FT.

Learn more about the cone here:

brainly.com/question/16394302

#SPJ1

6 0
2 years ago
If 2(x + 3) + 7x = 3(x - 2) - 9, then x = ?
Fudgin [204]

Answer:

x=− 7 over 2 =−3.500

Hope this helps!

5 0
3 years ago
Read 2 more answers
PLEASE HELP IMMEDIATELY! HURRY!
Fynjy0 [20]

Answer:

5 * 5 * 5 * 5

Step-by-step explanation:

Use the rules of Indices.

5⁶⁻²

= 5⁴

8 0
3 years ago
Read 2 more answers
Radio waves travel at the speed of light, approximately 300,000,000 m/s. Part A How much time does it take for a radio message t
jenyasd209 [6]

Answer:

Step-by-step explanation:

First you want to understand that every time a radio wave goes 300,000,000 meters a second passes, literally what meter per second means.    of course it doesn't go that far, it goes 384,000 one way and then the same distance back, which makes 768,000.  Under a third of the distance to make 1 second, so it will be less than one second.  

You also want to understand the formula for speed.  speed = distance / time.  Whch also means, to find time you can change it to be time = distance / speed.  And hey, we have distance and speed.  768,000 / 300,000,000 = .00256, I'll leave the significant figures to you unless you need help with them.  but that's .00256 of a second.  or .00256 s

7 0
3 years ago
Read 2 more answers
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