The probability of getting disease X (event A) is 0.65, and the probability of getting disease Y (event B) is 0.76. The probabil
2 answers:
Answer:
The events A and B are independent
Step-by-step explanation:
The occurrence of disease X is not impacting the chances of occurrence of disease Y. Thus, these two events have no relation with each other.
The probability of getting both the disease X and disease Y when they both are considered as two independent events
Thus , it can be said that the events A and B are independent
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Answer:
7 quarters are spent for throwing 350 food pebbles in pond.
Step-by-step explanation:
Given:
Reggie receives 50 food pebbles for every quarter he spends.
Number of food pebbles he has = 350
Let the number of quarters spent for 350 pebbles be 'x'.
Now, using proportion and cross multiplication method, we can find 'x'.
<u><em>1 quarter is equivalent to 50 pebbles thrown in pond.</em></u>
<u><em>So, 'x' quarters is equivalent to 350 pebbles thrown in pond.</em></u>
So, 7 quarters are spent for throwing 350 food pebbles in pond.
Answer:
Recall that a relation is an <em>equivalence relation</em> if and only if is symmetric, reflexive and transitive. In order to simplify the notation we will use A↔B when A is in relation with B.
<em>Reflexive: </em>We need to prove that A↔A. Let us write J for the identity matrix and recall that J is invertible. Notice that . Thus, A↔A.
<em>Symmetric</em>: We need to prove that A↔B implies B↔A. As A↔B there exists an invertible matrix P such that . In this equality we can perform a right multiplication by
and obtain
. Then, in the obtained equality we perform a left multiplication by P and get
. If we write
and
we have
. Thus, B↔A.
<em>Transitive</em>: We need to prove that A↔B and B↔C implies A↔C. From the fact A↔B we have and from B↔C we have
. Now, if we substitute the last equality into the first one we get
.
Recall that if P and Q are invertible, then QP is invertible and . So, if we denote R=QP we obtained that
. Hence, A↔C.
Therefore, the relation is an <em>equivalence relation</em>.