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nignag [31]
3 years ago
12

Find (fºg)(1) f(x) = x² - 1 g(x) = √x A.0 B.1 C.4 √2 D. √8

Mathematics
1 answer:
Savatey [412]3 years ago
4 0

Given:

The function are

f(x)=x^2-1

g(x)=\sqrt{x}

To find:

The value of (f\circ g)(1).

Solution:

We have,

f(x)=x^2-1

g(x)=\sqrt{x}

We need to find the value of (f\circ g)(1).

(f\circ g)(1)=f(g(1))            [\because (f\circ g)(x)=f(g(x))]

(f\circ g)(1)=f(\sqrt{1})            [\because g(x)=\sqrt{x}]

(f\circ g)(1)=f(1)      

(f\circ g)(1)=(1)^2-1                  [\because f(x)=x^2-1]

(f\circ g)(1)=1-1      

(f\circ g)(1)=0      

The value of (f\circ g)(1) is 0.

Therefore, the correct option is A.

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7 0
3 years ago
Find the range for the function: y=x-7 {-3,0,2,5}
trasher [3.6K]

Answer:

Range is : { -10, -7, -5, -2 }

Step-by-step explanation:

Given:

The function is given as:

y=x-7

The domain of the function = { -3, 0, 2, 5 }

A function's input is called its domain and a function's output is called its range.

The range depends on the domain values. So, the values of 'y' are the values of range and the values of 'x' are the values of domain.

Here, the domain is given as:

Domain = { -3, 0, 2, 5 }

We need to find the values of 'y' for each value of 'x' taken from the domain set.

Plug in x=-3. This gives,

y=-3-7=-10

Plug in x=0. This gives,

y=0-7=-7

Plug in x=2. This gives,

y=2-7=-5

Plug in x=-5. This gives,

y=5-7=-2

Therefore, the set of all values of 'y' is the range.

Range is equal to { -10, -7, -5, -2 }.

8 0
4 years ago
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VladimirAG [237]

Answer:

THE LENGTH OF SIDE=14cm

As,

Hypotenuse ²=Base²+Perpendicular ²

H²=13²+5²

H²=169+25

H²=196

H=14

6 0
3 years ago
Use your understanding of the constant of proportionality to determine k. If the relationship does not have a constant of propor
mihalych1998 [28]

Answer:

Far left: constant of proportionality= 3.4

Middle: q=12----COP=3

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3 0
3 years ago
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Answer:

210 in

Step-by-step explanation:

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3 years ago
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