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nignag [31]
3 years ago
12

Find (fºg)(1) f(x) = x² - 1 g(x) = √x A.0 B.1 C.4 √2 D. √8

Mathematics
1 answer:
Savatey [412]3 years ago
4 0

Given:

The function are

f(x)=x^2-1

g(x)=\sqrt{x}

To find:

The value of (f\circ g)(1).

Solution:

We have,

f(x)=x^2-1

g(x)=\sqrt{x}

We need to find the value of (f\circ g)(1).

(f\circ g)(1)=f(g(1))            [\because (f\circ g)(x)=f(g(x))]

(f\circ g)(1)=f(\sqrt{1})            [\because g(x)=\sqrt{x}]

(f\circ g)(1)=f(1)      

(f\circ g)(1)=(1)^2-1                  [\because f(x)=x^2-1]

(f\circ g)(1)=1-1      

(f\circ g)(1)=0      

The value of (f\circ g)(1) is 0.

Therefore, the correct option is A.

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HELP! I don't understand so please give a detailed explanation.
likoan [24]

From the picture, we can see that ΔLSP and ΔLRN are similar, so corresponding sides are proportionate:


LN : LP = 28:12 = 7:3


Therefore, the LRN sides is 7/3 of the corresponding side of LSP.


Then, it states that the area of LSP = 50, and area of a triangle is (1/2)bh, so we set up the equation


Area of LSP = (1/2)bh = 50 ← Remember how the corresponding sides are 7/3 of LSP? Therefore, the area of LRN:


LRN = (1/2)(7b/3)(7h/3) ← Take out the 7/3 and multiply them together

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