Answer:
12.2 hours
Step-by-step explanation:
You want to find t such that y = 2·y₀. That is, you want to solve
... 2y₀ = y₀·e^(0.0567t)
Dividing by y₀, you have
... 2 = e^(0.0567t)
and taking the natural log gives ..
... ln(2) = 0.0567t
... ln(2)/0.0567 = t ≈ 12.2248 . . . . divide by the coefficient of t
The doubling time is approximately 12.2 hours.
Answer:
f(x)=-4x+22
f(12)=-4×12+22=-48+22=-26 if your
Step-by-step explanation:
question is f(x)=-4x+22
Answer:
49% of the pupils are boys and 51% are girls.
Step-by-step explanation:
Alright, so first, you've got to find the total number of students: 567.
Now, to find the value of 1%, you divide 567 by 100, which will give you 5.67.
Next, you divide the number of male students by the value of 1%. That's 278 ÷ 5.67 = 49.0299823633157.
Subtracting that from 100% gives you 50.9700176366843 (percentage of girls)
Now, you can't write all that down, so you'll round it! 49.0299823633157 will round down, because 0 is less than 5, so it's 49%. 50.9700176366843 rounds up, because 9 is greater than 5, so that's 51%.
Therefore, 49% of the pupils are boys and 51% are girls.
I hope this helps!
W=33/8.7
w=3.79
i believe this is the answer
850.
68,750 = 350(75) + 50x
68, 750 = 26,250 + 50x
-26250
42,500 = 50x / 50
850 = x
