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LenaWriter [7]
3 years ago
6

What is the slope of the line in the graph? On a coordinate plane, a line goes through points (negative 2, negative 1) and (0, 1

).
Mathematics
2 answers:
dem82 [27]3 years ago
7 0

Answer:

The slope is one.

Step-by-step explanation:

You can use the formula (y1-y2)/(x1-x2). Plugging in the points, it would be

(-1-1)/(-2-0) which simplifies to -2/-2, then just 1. You can also make a graph if you really aren't sure whether you did the problem right or make the full equation and plug the points in to make sure it checks out. :) Hope that helps?

Katen [24]3 years ago
5 0

Answer:

the right answer is 2

You might be interested in
Which point lies on the graph of f(x) = -2(x + 3) – 5 A) (-6,1) B) (-6,-8) C) (6,-13) D) (6,-4)
nalin [4]
First you'd work around the parenthesis, getting you a reduced problem of -2x-6-5.

combine like terms to receive -2x-11

now treat the f(x) as Y and you'll get y=-2x-11; toss it onto a graph and plot the individual points (your answer options)

all points except for A do not touch the line, resulting in your answer to be letter A!

hope this helps :)
7 0
4 years ago
A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int
Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}

By expanding the previous equation:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0

Since there is no accumulation within the tank, expression is simplified to this:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}, where c(0) = 0 \frac{pounds}{gallon}.

\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}

The solution of this equation is:

c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})

The salt concentration after 8 minutes is:

c(8) = 0.166 \frac{pounds}{gallon}

The instantaneous amount of salt in the tank is:

m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds

3 0
3 years ago
The slope of the line below is 2. Which of the following is the point-slope form of the line? the x is 1 and the y is -1
sukhopar [10]
The point slope form would be y+1=m(x-1)


5 0
4 years ago
Read 2 more answers
A man standing on the roof of a building 64.0 feet high looks down to the building next door. He finds the angle of depression t
8_murik_8 [283]

Answer:

The height of the next door building is 41.7 feet

Step-by-step explanation:

* Lets study the situation in the problem

- The man standing on the roof of a building 64.0 feet high

- The angle of depression to roof of the next door building is 34.7°

- The angle of depression to the bottom of the next door building

  is 63.3°

- We need to find the height of the next door building

* Lets consider the height of the man building and the horizontal

 distance between the two building formed a right triangle and the

 angle of depression is opposite to the side which represented the

 height of the building

- Let the horizontal distance between the two buildings called x

# In the triangle

∵ The length of the side opposite to the angle of depression (63.3°)

  is 64.0

∵ The length of the horizontal distance is x which is adjacent to the

  angle of depression (63.3°)

- Use the trigonometry function tanФ = opposite/adjacent

∴ tan 63.3° = 64.0/x ⇒ use cross multiplication

∴ x (tan 63.3°) = 64 ⇒ divide both sides by (tan 63.3°)

∴ x = 64.0/(tan 63.3°)

∴ x = 32.1886 feet

- Lets use this horizontal distance to find the vertical distance between

  the roofs of the two buildings

* Lets consider the height of the vertical distance between the roofs

 of the two buildings  and the horizontal distance between the two

 building formed a right triangle and the

 angle of depression is opposite to the side which represented the

 vertical distance between the roofs of the two buildings

- Let the vertical distance between the roofs of the two buildings

 called y

# In the triangle

∵ The vertical distance between the roofs of the two buildings is y

   and opposite to the angle of depression (34.7°)

∵ The horizontal distance x is adjacent to the angle of

   depression (34.7°)

∴ tan (34.7°) = y/x

∵ x = 32.1886

∴ tan 34.7° = y/32.1886 ⇒ use the cross multiplication

∴ y = 32.1886 (tan 34.7°)

∴ y = 22.2884 ≅ 22.3 feet

∴ The vertical distance between the roofs of the two

   buildings is 22.3 feet

- The height of the next door building is the difference between the

  height of the man building and the vertical distance between the

  roofs of the two buildings

∴ The height of the next door building = 64.0 - 22.3 = 41.7 feet

7 0
3 years ago
PLEASE HELP ASAP !!!! WILL MARK BRAINLIEST
kakasveta [241]

Answer:

10

Step-by-step explanation:

We can write the equation 38=4y-2 because LZ and DO are equivalent

Isolate x:

38=4y-2

38+2=4y-2+2 (add 2, addition property of equality)

40=4y

40/4=4y/4 (divide by 4, division property of equality)

10=y

3 0
3 years ago
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