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KATRIN_1 [288]
3 years ago
15

the polynomial ky^3+3y^2-3 and 2y^3-5y+k when divided by (y-5) leave the same remainder in each case. Find the value of k.

Mathematics
1 answer:
marshall27 [118]3 years ago
3 0

Answer:

k=\frac{153}{124}

Step-by-step explanation:

According to the Remainder Theorem; when P(y) is divided by y-a, the remainder is p(a).

The first polynomial is :

p(y)=ky^3+3y^2-3

When p(y) is divided by y-5, the remainder is

p(5)=k(5)^3+3(5)^2-3

p(5)=125k+75-3

p(5)=125k+72

When the second polynomial:

m(y)= 2y^3-5y+k is divided by y-5.

The remainder is;

m(5)= 2(5)^3-5(5)+k

m(5)= 225+k

The two remainders are equal;

\implies 125k+72=225+k

\implies 125k-k=225-72

\implies 124k=153

k=\frac{153}{124}

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3 years ago
Solve for x. -0.65 + 0.45x = 5.4
FinnZ [79.3K]

Answer:

x = 13.444 ... (repeating decimal) or;

x = 13 4/9

Step-by-step explanation:

-0.65 + 0.45x = 5.4

First we will add 0.65 to each 'side' of the equation.

0.65 + (-0.65) + 0.45x = 0.65 + 5.4

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Input the numbers, and now the equation looks like this:

0 + 0.45x = 6.05

Remove the zero:

0.45x = 6.05

Divide each 'side' by 0.45.

0.45x ÷ 0.45 = 6.05 ÷ 0.45

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Input the numbers, and now the equation looks like this:

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We can also write this as:

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3 years ago
How many solutions does the system of equations below have? x+y=4 and x-y=6
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a_sh-v [17]

Answer:

10

Step-by-step explanation

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Fomular:

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where I donates the intensity of the earthquake and S be the intensity of the standard earthquake.

Calculation:

Consider that M1 be the magnitude Japanese earthquake and M2 be the magnitude of the Pennsylvania earthquake and L1 be the intensity of the Japanese earthquake and L2 the intensity of the Pennsylvania  earthquake.

Here the magnitude of the Japanese earthquake is M1 = 6.14 and the magnitude of the Pennsylvania is M2 = 3.1

By the use of magnitude of the earthquake fomular M = log I1/S, the intensity of the Japanese earthquake is calculated as follows .

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3 0
3 years ago
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