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leonid [27]
3 years ago
14

Can someone please explain how to answer #18?

Mathematics
1 answer:
swat323 years ago
4 0
Sorry, what grade is that for? might need to learn that right away
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18. 50 - [7 + (32 - 2)]
Nataly_w [17]

Answer:

13

Step-by-step explanation:

32-2=30

30+7=37

50-37=13

7 0
2 years ago
Read 2 more answers
The sum of two numbers is 12 and their difference is 18 what are the two numbers
lawyer [7]

Answer:


Step-by-step explanation:

x+y=12

x-y=18

Now eliminate the y by adding the two equations together to get

2x=30

x=15

then solve for y.

15+y=12

15-y=18

y= -3

3 0
3 years ago
On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes
belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

r = \frac{\Delta T_{X}}{\Delta T_{Y}}

r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}

r = 11\,\frac{^{\circ}X}{^{\circ}Y}

The difference between current temperature in Y linear scale with respect to freezing point is:

\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)

\Delta T_{Y} = 115\,^{\circ}Y

The change in X linear scale is:

\Delta T_{X} = r\cdot \Delta T_{Y}

\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)

\Delta T_{X} = 1265\,^{\circ}X

Lastly, the current temperature on the X scale is:

T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X

T_{X} = 1150\,^{\circ}X

The current temperature on the X scale is 1150 °X.

5 0
3 years ago
Which value is the 10th term in the sequence:-62,-47,-32,-17,-2?
balu736 [363]
The answer is 13
Sure!!!
5 0
3 years ago
Write the equation of the line, in slope-intercept form, that passes through the point (-8,-1) and that is parallel to x-3=0
nataly862011 [7]
Y=-5X which is the equation you use to figure out the answer
5 0
3 years ago
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