3 years ago

Can someone please explain how to answer #18?

Mathematics

1 answer:

swat323 years ago

4 0

Sorry, what grade is that for? might need to learn that right away

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18. 50 - [7 + (32 - 2)]

Nataly_w [17]

Answer:

Step-by-step explanation:

32-2=30

30+7=37

50-37=13

7 0

2 years ago

Read 2 more answers

The sum of two numbers is 12 and their difference is 18 what are the two numbers

lawyer [7]

Answer:

Step-by-step explanation:

x+y=12

x-y=18

Now eliminate the y by adding the two equations together to get

2x=30

x=15

then solve for y.

15+y=12

15-y=18

y= -3

3 0

3 years ago

On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes

belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

$r = \frac{\Delta T_{X}}{\Delta T_{Y}}$

$r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}$

$r = 11\,\frac{^{\circ}X}{^{\circ}Y}$

The difference between current temperature in Y linear scale with respect to freezing point is:

$\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)$

$\Delta T_{Y} = 115\,^{\circ}Y$

The change in X linear scale is:

$\Delta T_{X} = r\cdot \Delta T_{Y}$

$\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)$

$\Delta T_{X} = 1265\,^{\circ}X$

Lastly, the current temperature on the X scale is:

$T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X$

$T_{X} = 1150\,^{\circ}X$

The current temperature on the X scale is 1150 °X.

5 0

3 years ago

Which value is the 10th term in the sequence:-62,-47,-32,-17,-2?

balu736 [363]

The answer is 13
Sure!!!

5 0

3 years ago

Write the equation of the line, in slope-intercept form, that passes through the point (-8,-1) and that is parallel to x-3=0

nataly862011 [7]

Y=-5X which is the equation you use to figure out the answer

5 0

3 years ago