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BabaBlast [244]
3 years ago
8

A large school district in southern California asked all of its eighth-graders to measure the length of their right foot at the

beginning of the school year, as part of a science project. The data show that foot length is approximately Normally distributed, with a mean of 23.4 cm and a standard deviation of 1.7 cm. Suppose that 25 eighth-graders from this population are randomly selected. Approximately what is probability that the sample mean foot length is less than 23 cm?

Mathematics
1 answer:
Ber [7]3 years ago
4 0

Answer:

The probability of the sample mean foot length less than 23 cm is 0.120

Step-by-step explanation:

* Lets explain the information in the problem

- The eighth-graders asked to measure the length of their right foot at

  the beginning of the school year, as part of a science project

- The foot length is approximately Normally distributed, with a mean of

 23.4 cm

∴ μ = 23.4 cm

- The standard deviation of 1.7

∴ σ = 1.7 cm

- 25 eighth-graders from this population are randomly selected

∴ n  = 25

- To find the probability of the sample mean foot length less than 23

∴ The sample mean x = 23, find the standard deviation σx

- The rule to find σx is σx = σ/√n

∵ σ = 1.7 and n = 25

∴ σx = 1.7/√25 = 1.7/5 = 0.34

- Now lets find the z-score using the rule z-score = (x - μ)/σx

∵ x = 23 , μ = 23.4 , σx = 0.34

∴ z-score = (23 - 23.4)/0.34 = -1.17647 ≅ -1.18

- Use the table of the normal distribution to find P(x < 23)

- We will search in the raw of -1.1 and look to the column of 0.08

∴ P(X < 23) = 0.119 ≅ 0.120

* The probability of the sample mean foot length less than 23 cm is 0.120

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olga2289 [7]
We know that
area of the circle=pi*r²

if 360° (full circle) has an area of-------------> pi*r²
110°------------------------------> 40 units²
pi*r²=40*360/110--------> pi*r²=130.91------> r²=130.91/pi-----> r²=41.69
r=6.46 units

the answer is
the radius is 6.46 units
7 0
2 years ago
In one region, the september energy consumption levels for single-family homes are found to be normally distributed with a mean
tatyana61 [14]
The probability would be 0.1971.

We will calculate a z-score for each end of this interval.

z = (X-μ)/σ

For the lower limit:
z = (1100-1050)/218 = 50/218 = 0.23

For the upper limit:
z = (1225-1050)/218 = 175/218 = 0.80

Using a z-table (http://www.z-table.com) we see that the area under the curve to the left of, less than, the lower limit is 0.5910.  The area under the curve to the left of, less than, the upper limit is 0.7881.  To find the area between them, we subtract:

0.7881 - 0.5910 = 0.1971
6 0
3 years ago
Read 2 more answers
If f(x) = 2(x)^2 + 5 square root (x+2), complete the following statement (round your answer to the nearest hundredth): f(2) =
mojhsa [17]

f(x) = 2(x)^{2} +5 \sqrt{x+2}

f(2) = 2(2)^{2} + 5 \sqrt{(2)+2}

f(2) = 2(4) + 5\sqrt{4}

f(2) = 8 + 5(2)

f(2)= 8+10

f(2) = 18

3 0
3 years ago
The sum of three numbers is 24. Twice the middle number is 2 more than the largest number, and the largest number is equal to th
harina [27]

Answer:

  • x = 5, y = 7, z = 12

Step-by-step explanation:

<u>Let the numbers be x, y and z</u>

  • x + y + z = 24
  • 2y = z + 2
  • z = x + y

<u>Solving by substitution:</u>

  • x + y + z = z + z = 24
  • 2z = 24
  • z = 12

  • 2y = z + 2
  • 2y = 12 + 2
  • 2y = 14
  • y = 7

  • z = x + y
  • x = z - y
  • x = 12 - 7 = 5

<u>The answer:</u>

  • x = 5, y = 7, z = 12
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2 years ago
I got these wrong help needed plz !!
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