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s344n2d4d5 [400]
3 years ago
13

Which of the following is the correct factorization of the polynomial below?

Mathematics
1 answer:
diamong [38]3 years ago
7 0

Answer: correct answer is B.(2x+3y)(4x^2-6xy+9y^2)

8x^3 + 27y^3

(2x)^3+(3y)^3

(2x+3y)(4x^2-6xy+9y^2) <----answer

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Twice a number decreased by eight is sixteen.
Firlakuza [10]
The number is 12

16 plus 8 = 24/ 2= 12
7 0
2 years ago
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Wyatt invests $1200 into an account that earns 6.2% simple interest for 4 years. He does not make any other deposits or withdraw
iVinArrow [24]

Answer:

297.60 & 1497.60

Step-by-step explanation:

I had the question before and got it right

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2 years ago
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A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
You have a new pool and want to know it's volume. The pool is 5 feet deep and has a radius of 7 feet. About how much water can t
MrRa [10]

Answer:

769 cubic ft

Step-by-step explanation:

Its volume:

Find the volume of a cylinder of radius 7 ft and length 5 ft:

The basic formula for his volume is V = πr²h.  In this case, the volume is:

V = 3.14(7 ft)²(5 ft) = 769 cubic feet of water.

3 0
3 years ago
|13x-4|+12 &lt; 56<br> Anybody know this cuz I do
Ronch [10]

Answer:

\displaystyle x\in \left(-\frac{40}{13},\frac{48}{13}\right)

Step-by-step explanation:

<u>Inequalities with Absolute Value</u>

We must recall the following rule:

\text{If  }|M|0

Then:

-N

We have the following inequality:

|13x-4|+12 < 56

Subtracting 12:

|13x-4|< 56-12

|13x-4|< 44

Applying the rule:

-44

Adding 4:

-44+4

Operating:

-40

Dividing by 13:

\displaystyle -\frac{40}{13}

The solution expressed in interval form is:

\boxed{\displaystyle x\in \left(-\frac{40}{13},\frac{48}{13}\right)}

8 0
3 years ago
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