Question

|13x-4|+12 < 56 Anybody know this cuz I do

Answer 1

Answer:

$\displaystyle x\in \left(-\frac{40}{13},\frac{48}{13}\right)$

Step-by-step explanation:

Inequalities with Absolute Value

We must recall the following rule:

$\text{If }|M|0$

Then:

$-N$

We have the following inequality:

$|13x-4|+12 < 56$

Subtracting 12:

$|13x-4|< 56-12$

$|13x-4|< 44$

Applying the rule:

$-44$

Adding 4:

$-44+4$

Operating:

$-40$

Dividing by 13:

$\displaystyle -\frac{40}{13}$

The solution expressed in interval form is:

$\boxed{\displaystyle x\in \left(-\frac{40}{13},\frac{48}{13}\right)}$