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Alekssandra [29.7K]
3 years ago
12

Square root of 324x^4

Mathematics
1 answer:
Hatshy [7]3 years ago
4 0

Answer:

18x

Step-by-step explanation:

Rewrite, 324x² as 18x².

= √18x²

Pull terms out from under the radical, assuming positive real numbers.

18x

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Which of the following exponential functions represent the graph? ​
sdas [7]

Answer:

dodndbdie9ejrnfudowp2ejdnsmwo2oeidndndoep

5 0
3 years ago
Two groups of students were asked how far they lived from their school. The table below shows the distances in miles:
pychu [463]

Answer:

C. The value for Group A is double the value for Group B

Step-by-step explanation:

First, you add all the numbers from each group.

A: The distance in total is 39.06

B: The distance in total is 19.53

To find the mean, which is another way of saying the average, you divide the sum with how many numbers there are. (hope this makes sense, I suck at wording)

A: There are 9 numbers in total, hence, 39.06/9 = 4.34

B: There are 9 numbers in total, hence, 19.53/9 = 2.17

Those are the mean distance for the two groups.

2.17 * 2 = 4.34

Hence, C (third statement)

3 0
3 years ago
Read 2 more answers
Anyone willing to help out really quick?^^​
klemol [59]

Answer:

15.86 inches

Step-by-step explanation:

Area of rectangle = length times width

l = ∛81 inches

w = 3 2/3 inches

= l x w

= ∛81 x 3 2/3

= 15.86 inches

5 0
3 years ago
PLEASE HELP FAST The Booster Club raised $30,000 for a sports fund. No more money will be placed into the fund. Each year the fu
zloy xaker [14]

Answer:

c. $24,435

Step-by-step explanation:

30000(1 - .05)^{4} = 24,435.19

3 0
3 years ago
Can a math equation be like this:
ANTONII [103]

Answer:

  • Yes

Step-by-step explanation:

As per given information there are 18000 CCTV cameras in the area of 783.8 square kilometers

To find the average number of cameras you divide the number by the area.

The average number of CCTV cameras per square kilometer in NYC = 18000/783.8 = 22.9650421026 ≈ 23

It should be rounded up if taking approximate number

Yes you can have as many equal signs as you need and the approximately equal sign in the same equation.

8 0
3 years ago
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