F'(x)=-2x{e^(-x²)}
Equating f'(x)=0,
i.e,
-2x{e^(-x²)}=0....eqn(i)
For maximum slope:
Differentiating (i) wrt x,we get,
4x² {e^(-x²)}-2 {e^(-x²)}=0
{e^(-x²)} [4x²-2]=0
4x²-2=0
x=1/√2
If f(x)=y then f'(x)=dy/dx=slope
So,
Maximum slope
= f'(x)
= -2x{e^(-x²)}
=-2×(1/✓2){e^(-1/✓2)²}
= -✓2{e^(-1/2)}
=(-sqrt 2/sqrt e)
=-sqrt(2/e)➡c is correct
Answer:
9x^2 + 10x + 29
Step-by-step explanation:
Let's sort the x^2, the x and the numbers without an x:
First, the x^2
3x^2 + 16x^2 - 10x^2
So that's 3 + 16 - 10 if we ignore the x^2.
We can simplify this to 9x^2, because 3+16-10=9.
The same for the x:
1x + 15x - 6x = 10x
And then there's the lone 7 and 22.
7 + 22 = 29
So to summarize:
9x^2 + 10x + 29
Answer:
the opposite
Step-by-step explanation:
Answer:
Step-by-step explanation:
We know that exponential formula of depreciation

where
P is the initial amount
x is the interest rate
A is the amount after t years
we are given
The annual rate of depreciation, x, on a car that was purchased for $9,000
so, P=9000
we can plug value it

we are given
when x=5 , A=4500
so, we can plug it and solve for x





so, interest rate is 13%
now, we can plug x
and we get


Graph:
The answer to the question is c. If you are in multiplying, 8(2)= 16 & 3(3)= 9