Answer:

Step-by-step explanation:
we are given half-life of PO-210 and the initial mass
we want to figure out the remaining mass <u>after</u><u> </u><u>4</u><u>2</u><u>0</u><u> </u><u>days</u><u> </u>
in order to solve so we can consider the half-life formula given by

where:
- f(t) is the remaining quantity of a substance after time t has elapsed.
- a is the initial quantity of this substance.
- T is the half-life
since it halves every 140 days our T is 140 and t is 420. as the initial mass of the sample is 5 our a is 5
thus substitute:

reduce fraction:

By using calculator we acquire:

hence, the remaining sample after 420 days is 0.625 kg
Answer:
15 weeks
The amount of money is 270
Step-by-step explanation:
You: 60 +14x
Sister: 120+10x
Set them equal to each other
60+14x = 120+10x
Subtract 10x from each side
60+4x= 120
Subtract 60 from each side
4x= 60
Divide by 4
4x/4 = 60/4
x = 15
15 weeks
The amount of money is 120+10*15 = 120+150 = 270
Answer:
Case1:
Men : 30
Work : 1
Time (day×hr): 56×6 = 336 hr.
Case2:
Men : let it be m men.
Work: 1
Time: 45×7 = 315 hr.
Work being constant in both cases, men and time are in inverse proportion i.e, more men take less time.
Product of men and time is constant in both cases.
Therefore, 30×336=m×315
Or, 30×336/315 = m
Or, m = 32.
Hence, required number of men is 32.
Step-by-step explanation:
Answer:


Step-by-step explanation:
Let's call x the length of each piece in yards
If the ribbon is cut into 8 equal pieces then the sum of the pieces is:

Then:

Now we solve the equation for x

Divide both sides of equality by 8


So the length of each piece is
of a yard.
This is: 1.125 yards