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Komok [63]
4 years ago
15

Using the square root property: How would I solve this equation- (2x-3) Squared =18

Mathematics
2 answers:
WINSTONCH [101]4 years ago
8 0
(2x-3)^2=18\ \ \ \ | make\ \sqrt{}\\\\
|2x-3|=\sqrt{18}\\\\
2x-3=\sqrt{18}\ \ \ or\ \ \ -2x+3=\sqrt{18}\\\\
2x=\sqrt{18}+3\ \ \ \ or\ \ \ \ -2x=\sqrt{18}-3\\\\
x=\frac{\sqrt{9*2}+3}{2}\ \ \ or\ \ \ \ x=\frac{\sqrt{9*2}-3}{-2}\\\\
x=\frac{3\sqrt{2}+3}{2}\ \ \ or\ \ \ \ x=\frac{-3\sqrt{2}+3}{2}
qaws [65]4 years ago
7 0
(2x-3)^2=18\\
2x-3=\sqrt{18} \vee 2x-3=-\sqrt{18}\\
2x=3+3\sqrt{2} \vee 2x=3-3\sqrt{2}\\
x=\frac{3+3\sqrt{2}}{2} \vee x=\frac{3-3\sqrt{2}}{2}\\

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