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DIA [1.3K]
3 years ago
5

Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = ln(x), [1, 5]

Mathematics
1 answer:
matrenka [14]3 years ago
5 0

Answer:

Yes, the function satisfies the hypothesis of the Mean Value Theorem on the interval [1,5]

Step-by-step explanation:

We are given that a function

f(x)=ln(x)

Interval [1,5]

The given function is defined on this interval.

Hypothesis of Mean Value Theorem:

(1) Function is continuous on interval [a,b]

(2)Function is defined on interval (a,b)

From the graph we can see that

The function is continuous on [1,5] and differentiable at(1,5).

Hence, the function satisfies the hypothesis of the Mean Value Theorem.

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p=-1/3

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Step-by-step explanation:

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What property is 5x6x7=5x7x6
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What is the equation in point slope form of the line that passes through the point (−1, −3) and has a slope of 4?
Firlakuza [10]

Answer:

(y-(-3))=4(x-(-1))

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6 0
4 years ago
The Print Shop provides copying services to the general public. The Print Shop has equipment which is capable of making 1,800 co
steposvetlana [31]

a) The financial analysis determining the acceptance of the special order is as follows:

Data and Financial Analysis:

Capacity of photocopier per hour = 1,800 copies

Practical capacity of equipment = 7 hours

Total copies in a day = 12,600 (1,800 x 7)

Steady demand per day = 10,000

Variable cost per copy = $0.22

Service price per copy = $0.25

Profit per copy = $0.03 ($0.25 - $0.22)

Normal profit based on steady demand of 10,000 = $300 ($0.03 x 10,000)

Profit based on maximum capacity of 12,600 = $378 ($0.03 x 12,600)

Price per copy for the special customer = $0.24

Profit per copy based on special price of $0.24 = $0.02 ($0.24 - $0.22)

Profit from special customer with 5,000 pages = $100 (5,000 x $0.02)

Profit from other probable customers = $228 (7,600 x $0.03)

Lost profit for accepting special order based on maximum capacity = $50 ($378 - $228 - $100)

Lost profit if order is <u>not accepted</u> and demand is only 10,000 copies = $78 ($378 - $300)

  • Therefore, the special order at $0.24 should be accepted.

b) The largest order from customer that the shop could accept = 5,000 + $50/$0.02

= 5,000 + 2,500

= 7,500 copies

Thus, if the customer orders 7,500 copies to be made, the shop can still realize a maximum profit of $378 by accepting orders for additional 5,100 (12,600 - $7,500) copies from others.

Learn more: brainly.com/question/22599880

7 0
3 years ago
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