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3 years ago

Math homework help?

Mathematics

1 answer:

charle [14.2K]3 years ago

6 0

3r = 45/x= 45/x= 45 r = 45/3 = 15 mph The speed of PandD = 15 mph

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For the function F(x)=1/x,which of these could be a value of F(x) when x is close to zero

fomenos

Answer:

C. -10,000

Step-by-step explanation:

As x approaches zero, f(x) approaches infinity or negative infinity.

Answer: C. -10,000

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3 years ago

Answer quick please! Help fast!!

kolezko [41]

C, because when you add 45 on both sides, and then after that when you have to subtract 15 in both sides, you get 0 = 120.

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Consider a local community of a rock chucks in Wyoming that are increasing at a rate of 11% per month. Using the Rule of 70, ans

natka813 [3]

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3 years ago

Help urgent please.

zhuklara [117]

Answer:

The answer is D

Step-by-step explanation:

Plug any x value for the y values of f(x) and g(x)

Let's do 0 since it is easier.

f(x)=-2(0)-4=-4

g(x)=-2(0)+2=2

So, g(x) is 6 greater than f(x).

Thus, g is most likely moved 6 units up from f.

Graph the 2 functions on Desmos for a better picture.

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2 years ago

If f(x) =-2+8 and g(x) = square root of x+9 which statement is true

lidiya [134]

The statement that -6 is in the domain of f(g(x)) is true

<h3>Complete question</h3>

If f(x) = -2x + 8 and g(x) = $\sqrt{x + 9$ , which statement is true?

-6 is in the domain of f(g(x))
-6 is not in the domain of f(g(x))

<h3>How to determine the true statement?</h3>

We have:

f(x) = -2x + 8

$g(x) = \sqrt{x + 9$

Start by calculating the function f(g(x)) using:

f(g(x)) = -2g(x) + 8

Substitute $g(x) = \sqrt{x + 9$

$f(g(x)) = -2\sqrt{x + 9} + 8$

Set the radicand to at least 0

$x + 9 \ge 0$

Subtract 9 from both sides

$x \ge -9$

This means that the domain of f(g(x)) are real numbers greater than or equal to -9. i.e. -9, -8, -7, -6, ...........

Hence, the statement that -6 is in the domain of f(g(x)) is true