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monitta
4 years ago
12

A population has a mean and a standard deviation . Find the mean and standard deviation of a sampling distribution of sample mea

ns with sample size n. nothing ​(Simplify your​ answer.) nothing ​(Type an integer or decimal rounded to three decimal places as​ needed.)
Mathematics
1 answer:
grin007 [14]4 years ago
8 0

Complete Question

A population has a mean mu μ equals = 77 and a standard deviation σ = 14. Find the mean and standard deviation of a sampling distribution of sample means with sample size n equals = 26

Answer:

The mean of sampling distribution of the sample mean ( \= x) is \mu_{\= x } =  77

The standard deviation of sampling distribution of the sample mean ( \= x) is  

    \sigma _{\= x} = 2.746

Step-by-step explanation:

From the question we are told that

    The population mean is  \mu  =  77

     The  standard deviation is  \sigma =  14

     The sample size is  n  =  26

     

Generally the standard deviation of sampling distribution of the sample mean ( \= x) is  mathematically represented as

           \sigma _{\= x} =  \frac{ \sigma }{ \sqrt{n} }

substituting values  

          \sigma _{\= x} =  \frac{  14}{ \sqrt{26} }

          \sigma _{\= x} = 2.746

Generally the mean of sampling distribution of the sample mean ( \= x) is  equivalent to the population mean i.e  

      \mu_{\= x } =  \mu

      \mu_{\= x } =  77

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love history [14]

Answer:

Each Jersey: $6.75

Each pair of socks: $7.47

Sales tax: $1.03

Step-by-step explanation:

$22.00 total.

$1.03 sales tax.

$6.75 jersey x2 = $13.50

$13.50 + $1.03 = $14.53 jerseys & sales tax.

$22.00 - $14.53 =7.47


5 0
4 years ago
Read 2 more answers
a flask that weights 345.8g is filled with 225 ml of carbon tetrachloride. Together they weight 703.55g. Calculate density in g/
alina1380 [7]
 703.55  minus the flask weight
-345.8  equals
<span> <span> <span> 357.75 </span> </span> </span>

density = 357.75 / 225 = 1.59 grams / milliliter
density = 1,590 grams / liter



4 0
3 years ago
How do I work this out
Iteru [2.4K]
If the track is 10km long, and X travels at 40 km/h, it will take 1 hour to do 4 laps. this means that car X will do one lap in 15 minutes. Y travels at 30 km/h, which means it will do 3 laps in 1 hour, meaning that car X will do 1 lap in 20 minutes.

X- 15, 30, 45, 60
Y-20, 40, 60


Therefore, after an hour, they will pass again.
5 0
4 years ago
The sum of a number and five times its reciprocal is 4.5. Write a quadratic equation for the number, and use the quadratic formu
g100num [7]

Answer:

x= -2 and (x+3)=0, x= -3

Step-by-step explanation:

"The sum of a number" well we do not know what the number is right, so let's call the number x. So we know we have x and we are adding it to something because it says sum. What are we adding it to? "5 times its reciprocal". A reciprocal of a number is equal to 1/the number. So the reciprocal of x is just 1/x. But we want 5 times this so multiply by 5. So now we have x + 5(1/x). Now we need to set it equal to something to be able to solve it. The problem says the sum of a number and 5 times its reciprocal is -6, so x + 5(1/x) = -6. Now just use order of operations to solve for x. First multiply: x + 5/x =-6. Then the next stperfect is harder because we want to get x by itself but we have x + 5/x. A trick you can do here is multiply the whole equation by x. This cancels out the fraction for us: x(x + 5/x) = -6(x) becomes x^2 +5 = -6x. Now we have a quadratic equation, to solve this you have to Factor or use the quadratic formula. I'll try factoring: first we need all of the terms on one side: x^2 +5x +6 =0. Now we need factors of 6 that add or subtract to 5. There are a couple of options here we could use 6 and -1 or 2 and 3. 6 and -1 would not work because both signs in the equation are plus which means we need our factors to both be positive, also if you tried 6 and -1 and then foiled out the factors to check it, it would not work. So 2 and 3 have to be the factors so the equations equals (x+2)(x+3)=0. Now we set each factor equal to zero and solve for x: (x+2)=0, x= -2 and (x+3)=0, x= -3. Those are the two numbers that would work! Hope this helps!!

5 0
3 years ago
Read 2 more answers
Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 L of a dyesolution with a c
nordsb [41]

Answer:

Time,t that it will elapse before the concerntration of the dye in the tank reaches1% of its original value is 460.52 seconds

Step-by-step explanation:

Let Q(t) = amount of dye for all time,t.

Let Q'= rate in - rate out.

But Q/200 = concerntration of dye

Therefore rate out= Q/200 ×2.

Q'/Q = - 1/100

Dividing by Q gives

Ln/Q/ + c = -1/100t + c1

Integrating both sides with respect to t

Ln/Q/ = -1/100t + c2.

c1 and c1 are just another constants

Q= c3e^-t/100

Exponentiating both sides will cause the absolute values to get absorbed into the constants giving rise to a new constant c3

200= c3-0/100

c3= 200

2= 200e^-t/100

Ln1/100= - t/100

Ln0.01 = - t/ 100

Cross multiply

t= Ln0.01 × 100

t = 4.6052 ×100

t = 460.52seconds

7 0
3 years ago
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