Answer = c
Step-by-step explanation:Since the medians are approximately the same they lost on average around the same amount regardless of exercise. Notice that the range of those with exercise is smaller though so they were more consistent in the amount of weight lost.
Answer:
use a ruler
or
buy a graph
Step-by-step explanation:
Not the best answer tho... becuase this useless Mod deleted all my answers randomly
Answer:
ASA and AAS
Step-by-step explanation:
We do not know if these are right triangles; therefore we cannot use HL to prove congruence.
We do not have 2 or 3 sides marked congruent; therefore we cannot use SSS or SAS to prove congruence.
We are given that EF is parallel to HJ. This makes EJ a transversal. This also means that ∠HJG and ∠GEF are alternate interior angles and are therefore congruent. We also know that ∠EGF and ∠HGJ are vertical angles and are congruent. This gives us two angles and a non-included side, which is the AAS congruence theorem.
Since EF and HJ are parallel and EJ is a transversal, ∠JHG and ∠EFG are alternate interior angles and are congruent. Again we have that ∠EGF and ∠HGJ are vertical angles and are congruent; this gives us two angles and an included side, which is the ASA congruence theorem.
Plug in each of the answer choices into the 'y=' button and check each table. If all of the ordered pairs are shown in one equation table, then that is your representing function.
Answer:
A. 1/32
Step-by-step explanation:
Ok, the probability for one of the coins to land on heads is 1/2 cause a coin have to sides and chance is 50% that it will land on either of its sides.
If you have 2 coins the probability will be 1/2 for the first coin to land on heads and 1/2 for the second one. The overall probability for 2 coins would be (1/2)*(1/2)=1/4. You could also see it is 1/4 because all of the possible combinations of 2 coins are 4 (HH, HT, TH, TT) and HH is one of four.
It's the same if you have 5 coins. The probability will be (1/2)*(1/2)*(1/2)*(1/2)*(1/2)=1/32 in other words HHHHH is one of 32 possible combinations of 5 coins.
