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Zinaida [17]
2 years ago
8

The table shows the elevation of four swimmers. Which swimmer dives down the farthest?

Mathematics
2 answers:
jonny [76]2 years ago
5 0

Answer:

D

Step-by-step explanation:

anastassius [24]2 years ago
4 0

Answer:

the answer is Swimmer D

Step-by-step explanation:

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Reply with quote<br> {(-1,3),(0,5),(1,7),(2,9)} , identify the domain and range
Contact [7]

The domain is -1,0,1,2. The range is 3,5,7,9.

4 0
3 years ago
How many solutions does the system of equations have?<br> 6x+y=2<br> -18x+3y=12
Tamiku [17]
There will be one solution. To solve that:
1. Get the y alone by switching the places.
6x+y=2 > y=2-6x 
-18x+3y=12 > 3y=12-18x > Then divide 3 on each number > y=4-6x
After doing that, you can solve this in graphing or algebra way.

Ima do the algebra way: 

SO we have 2 system of equations. Now pick one equestion.
I will pick, y=2-6x. Now Ima replace the Y with the other equation y=4-6x >  
4-6x=2-6x.

Now solve. And get >  0 aka Infinite Solution.
6 0
3 years ago
Read 2 more answers
Someone help I've re-taken this test like 3 times now!!!
Masja [62]

Answer:

the center is around 5

Step-by-step explanation:

that's just a guess, it seems to be the one that makes the most sense to me

6 0
3 years ago
Find the measure of angle y. Round your answer to the nearest hundredth. Right triangle
e-lub [12.9K]
<h3>The measure of angle y is 35.68 degrees</h3>

<em><u>Solution:</u></em>

Given that,

hypotenuse 12

Opposite 7

Find the measure of angle y

y is unknown and is between the hypotenuse and adjacent side

The figure is attached below

In a right triangle, the sine of the angle is the ratio of the side opposite to the angle to the hypotenuse

Therefore,

sin\ y = \frac{opposite}{hypotenuse}\\\\sin\ y = \frac{7}{12}\\\\sin\ y = 0.5833\\\\y = sin^{-1}\ 0.5833\\\\Use\ arcsin\ calculator\\\\y = 35.6829 \\\\y \approx 35.68

Thus measure of angle y is 35.68 degrees

7 0
3 years ago
Can someone help me?!
Crank

The answer is D. dividing both sides by 4 isolates the variable

3 0
3 years ago
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