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Zinaida [17]
3 years ago
8

The table shows the elevation of four swimmers. Which swimmer dives down the farthest?

Mathematics
2 answers:
jonny [76]3 years ago
5 0

Answer:

D

Step-by-step explanation:

anastassius [24]3 years ago
4 0

Answer:

the answer is Swimmer D

Step-by-step explanation:

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Which of the following numbers are greater than -0.33?
Rufina [12.5K]

Answer:

A and C

Step-by-step explanation:

B is -0.33, which is equal to -0.33

C is positive, which is automatically greater than -0.33

For A, -0.3 is greater than -0.33, sorry I'm not good at describing

4 0
3 years ago
If anna's test grades 66, 90, and 99, what is her test average?
Maksim231197 [3]

Answer:

85

Step-by-step explanation:

Average calculator

5 0
2 years ago
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vazorg [7]

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3 0
3 years ago
How is this solved using trig identities (sum/difference)?
GenaCL600 [577]
FIRST PART
We need to find sin α, cos α, and cos β, tan β
α and β is located on third quadrant, sin α, cos α, and sin β, cos β are negative

Determine ratio of ∠α
Use the help of right triangle figure to find the ratio
tan α = 5/12
side in front of the angle/ side adjacent to the angle = 5/12
Draw the figure, see image attached

Using pythagorean theorem, we find the length of the hypotenuse is 13
sin α = side in front of the angle / hypotenuse
sin α = -12/13

cos α = side adjacent to the angle / hypotenuse
cos α = -5/13

Determine ratio of ∠β
sin β = -1/2
sin β = sin 210° (third quadrant)
β = 210°

cos \beta = -\frac{1}{2}  \sqrt{3}

tan \beta= \frac{1}{3}  \sqrt{3}

SECOND PART
Solve the questions
Find sin (α + β)
sin (α + β) = sin α cos β + cos α sin β
sin( \alpha + \beta )=(- \frac{12}{13} )( -\frac{1}{2}  \sqrt{3})+( -\frac{5}{13} )( -\frac{1}{2} )
sin( \alpha + \beta )=(\frac{12}{26}\sqrt{3})+( \frac{5}{26} )
sin( \alpha + \beta )=(\frac{5+12\sqrt{3}}{26})

Find cos (α - β)
cos (α - β) = cos α cos β + sin α sin β
cos( \alpha + \beta )=(- \frac{5}{13} )( -\frac{1}{2} \sqrt{3})+( -\frac{12}{13} )( -\frac{1}{2} )
cos( \alpha + \beta )=(\frac{5}{26} \sqrt{3})+( \frac{12}{26} )
cos( \alpha + \beta )=(\frac{5\sqrt{3}+12}{26} )

Find tan (α - β)
tan( \alpha - \beta )= \frac{ tan \alpha-tan \beta }{1+tan \alpha  tan \beta }
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3}   }{1+(\frac{5}{12}) ( \frac{1}{2} \sqrt{3})}

Simplify the denominator
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3}   }{1+(\frac{5\sqrt{3}}{24})}
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }

Simplify the numerator
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{6}{12} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }
tan( \alpha - \beta )= \frac{ \frac{5-6\sqrt{3}}{12} }{ \frac{24+5\sqrt{3}}{24} }

Simplify the fraction
tan( \alpha - \beta )= (\frac{5-6\sqrt{3}}{12} })({ \frac{24}{24+5\sqrt{3}})
tan( \alpha - \beta )= \frac{10-12\sqrt{3} }{ 24+5\sqrt{3}}

7 0
3 years ago
The figure is formed from rectangles. Find the total area.
hram777 [196]

Answer:

The answer to your question is 68 ft²

Step-by-step explanation:

Data

                           Large square                Small square

base                       10 - 2 = 8 ft                       2 ft

height                         8 ft                                2 ft

Process

1.- Find the area of the large square

Area = base x height

        = 8 x 8

        = 64 ft²

2.- Find the are of the small square

Area = base x height

Area = 2 x 2

        = 4 ft²

3.- Find the total area

Total area = 64 + 4

                 = 68 ft²      

3 0
4 years ago
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