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tatiyna
3 years ago
15

Simplify: 3x + 9 +2x-3

Mathematics
2 answers:
castortr0y [4]3 years ago
4 0

Answer:

3x + 9 + 2x -3

add like terms for the answer of:

5x + 6

so 5x + 6 is the answer

Zigmanuir [339]3 years ago
4 0

Answer:

it might be: 5x+6

Step-by-step explanation:

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Please go to my profile and answer my last question
Alex Ar [27]

Answer:

ok

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Tracy needs to find the length and width of the equipment storage room where she works. The room is 2 meters longer than it is w
____ [38]

Answer:

3 meters

Step-by-step explanation:

We assume the storage room is a rectangle, like most rooms, no indication it is otherwise.

We know it's a rectangle and not a square because it is longer than wide.

We have the perimeter measurement (16 meters).

So, we can make the following equation:

2x + 2y = 16

x being the width of the room, y being it's length.  A perimeter is the sum of all sides.

We also know the room is 2 meters longer than wide... so:

y = x + 2

If we replace y in the first equation by its value relative to x, we get:

2x + 2(x + 2) = 16 which becomes

2x + 2x + 4 = 16

4x =12

thus x = 3

Width: 3 meters

Length: 5 meters.

Confirms the 16 meters perimeter.

5 0
3 years ago
Read 2 more answers
The midpoint of K is M(-3, -1). One endpoint is J(-12, -11). What are the coordinates of endpoint K?
Over [174]

Answer: 2 times sqrt(181) (approximately 26.9)

Step-by-step explanation:

First, we can plot these points on a graph. Then, we’ll use the Distance Formula to calculate the distance between the two points, which is sqrt(181).


Since the problem tells us that one of our coordinates is the midpoint of K, we know that the length of the segment we just calculated is 1/2 of K. We can multiply our answer to get that K is 2 times sqrt(181).

7 0
1 year ago
Read 2 more answers
Fill in the blank to make the expression a perfect square.. . u^2-16u+?
hram777 [196]
U² - 16 u + 64 = ( u - 8 )²
because: A² - 2 A B + B² = ( A - B )²
Answer: 64
8 0
3 years ago
The roots of the quadratic equation $z^2 + bz + c = 0$ are $-7 + 2i$ and $-7 - 2i$. What is $b+c$?
Alexxx [7]

Answer:

67

Step-by-step explanation: Given the quadratic equation $z^2 + bz + c = 0$, Vieta's formulas tell us the sum of the roots is $-b$, and the product of the roots is $c$. Thus,

\[-b = (-7 + 2i) + (-7 - 2i) = -14,\]so $b = 14.$

Also,

\[c = (-7 + 2i)(-7 - 2i) = (-7)^2 - (2i)^2 = 49 + 4 = 53.\]Therefore, we have $b+c = \boxed{67}$.

There are many other solutions to this problem. You might have started with the factored form $(z - (-7 + 2i))(z - (-7 - 2i)),$ or even thought about the quadratic formula.

This is the aops answer :)

8 0
2 years ago
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