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Umnica [9.8K]
3 years ago
5

A 9​-pound bag of wildflower seed covers 15 square feet. How many pounds of seed does it take to cover 1 square​ foot?

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
8 0

Answer:

It would take .6 lbs of seed to cover 1 square foot

Step-by-step explanation:

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Write and graph an inequality that represents the numbers that are not solutions of each inequality.
o-na [289]
A.) x + 8 < 14
-8 -8
x < 6
b.) x - 12 >/= 5.7
+12 +12
x >/= 17.7
8 0
3 years ago
A shepherd is paid rs.2400 for gazing 18 cows for 5 weeks.How much will be paid for gazing 20 cows for 8 weeks?
lys-0071 [83]

Answer:

Rs. 4266.67(approx) will be paid for gazing 20 cows for 8 weeks.

Explanation:

A shepherd is paid rs. 2400 for gazing 18 cows for 5 weeks .

⇒ Number of money paid for gazing 1 cow for 1 week is, \frac{2400}{18\times 5} =\frac{400}{15}= \frac{80}{3}

then,

for gazing 20 cows for 8 weeks is=  Rs. \frac{80}{3}\times (20\times 8)

Therefore, the amount paid for gazing 20 cows for 8 weeks is, \frac{80 \times 160}{3} = \frac{12800}{3} = Rs. 4266.66667 or Rs. 4266.67(approx)

7 0
3 years ago
A scientific model doesn’t need to be something physical. It can also be a mathematical __________
MAVERICK [17]

Answer:

2+4

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
4-58. Lisa plans to retire on her 61st birthday. On her
mojhsa [17]

Answer:

Lisa invest "$2180.81" in her bank.

Step-by-step explanation:

The given values are:

On Lisa's 62nd birthday,

she withdraw = $10,000

The annuity of $A will remain at 3 percent for 40 years. The retirement pension of $10000 lasts 23 years at rate percentage of 3 but begins 40 years later.

⇒  A\times (\frac{P}{A} ,3 \ percent,40) - 10000 (\frac{P}{A} ,3 \ percent,23)\times \frac{1}{(1.03)40} = 0

⇒  A\times 23.1148 - 10000\times 16.4436\times 0.3066 = 0

⇒  A = 10000\times 16.4436\times \frac{0.3066}{23.1148}

⇒      = 10000\times 16.4436\times 0.0132

⇒      =2180.81 ($)

4 0
3 years ago
Listed below are time intervals​ (min) between eruptions of a geyser. Assume that the​ "recent" times are within the past few​ y
Shalnov [3]

Answer:

p value = 0.039

t = - 2.169

Step-by-step explanation:

Applying the null and alternate hypothesis

H_{0} : U1 = U2

H_{\alpha } : U1 \neq U2

using excel worksheet to calculate for ( t and p )

t = -2.169

p = 0.039

from the results obtained

The conclusion is affected by the significance level because : 0.1 < p > 0.01

so when the significance level  is = 0.1 the Null hypothesis is rejected and we can say the mean time interval will change  while

if the significance level = 0.01 the Null hypothesis is accepted and we can not say the mean time interval has changed because the p -value is greater than 0.01

attached is the excel solution

7 0
3 years ago
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