6×2/3 to the negative first power

Mathematics

1 answer:

Ierofanga [76]2 years ago

3 0

Answer:

1/4

Step-by-step explanation:

You might be interested in

Plz help me well mark brainliest if correct!.,

AlekseyPX

Answer: The perimeter is 20 cm

Step-by-step explanation: The top and bottom are same length, so 6+6, and the sides are the same length, so 4+4 don’t forget it’s cm and it becomes 20 cm.

PERIMITER = ADDING ALL SIDES

AREA = MULTIPLYING

6 0

2 years ago

Inverse laplace of [(1/s^2)-(48/s^5)]

Katen [24]

**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform $F(s)$ and $G(s)$ , then $\mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}$

Given that $\dfrac{1}{s^2} = \dfrac{1!}{s^2}$ and $-\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}$

From Table of Laplace Transform, you have $\mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}}$ and hence $\mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}$ .

Hope this helps...

7 0

3 years ago

A pharmaceutical company has developed a test for a scarce disease that is present in 0.5% of the population. The test is 98% ac

ioda

The probability is 3%

5 0

3 years ago

Read 2 more answers

Help help please anyone!!

amid [387]

Since 2=3
And 3 and 7 are on a straight line so they add up to 180
You can say : x+ 2x= 180
3x=180
x=180/3
x= 60
Angle 2 is 60

3 0