Hey there!
If we would want to find out what it would be, we would have to divide it.
Your correct answer would be (2.98)
I did 65.56/22.
Hope this helps you!
Could you retake the picture it’s hard to read
First, you have to find the median, which is the number in the middle: 25
Then cut the data in half by the median, so your new data sets are
15,29,20
and
31,38,41
Now you find the median of both of those sets, which is 29 and 38.
The interquartile range is the difference between the numbers, so 38-29 = 9.
The area of a square is
s • s
We can also write this as
s^2
So, for any side length “s”, we can make a function, A(s), such that
A(s) = s^2
Now that we have a quadratic equation for the area of a square, let’s go ahead and solve for the side lengths of a square with a given area. In this case, 225 in^2
225 = s^2
Therefore,
s = sqrt(225)
s = 15
So, the dimensions are 15 x 15 in
As an improper fraction, it is
.
