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ipn [44]
3 years ago
13

Andy runs 436.8 meters in 62.08 seconds.if Andy runs at a consistent speed how fast does he run in one second? Give your answer

to the nearest tenth of a second. And show your work
Mathematics
1 answer:
Zina [86]3 years ago
6 0
Andy runs 7 meters per second.

436.8/62.08 = x/1
436.8/62.08=7.04
7.04/1 =7.0/1

Hope that help!:)
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A truck is painting traffic lines along a highway.The truck paints 8 miles of lines in 3 hours.At that rate, how many miles can
bekas [8.4K]
The answer would be 32 miles (I think) if you set up a proportion you should get this answer.
7 0
3 years ago
Read 2 more answers
sid and Jill hiked 4 1/8 miles in the morning and 1 1/7 miles in the afternoon.how many times as far did they hike in the mornin
mote1985 [20]
Your answer is ..
First,
we have to turn our mixed fractions into an improper fraction.
=4 1/8 which is 33/8(4 x 8 + 1).

Our next mixed fraction,
we have 1 1/7 which is 8/7(1 x 7 + 1).

Now, we have the get the same denominator in order to subtract.
SO, both 8 and 7 goes in to 56. So we multiply both mixed fractions to get the same denominator.
(Tip: what ever you do to do numerator, you do to the denominator; and the other way around).
33/8 : 33*7=231 and our denominator, 8*7=56
So our improper fraction now,
231/56

Our next fraction 8/7,
7*8= 56 and our numerator 8*8=64.
=64/56

So, now we subtract.
231-64= 167 and our common denominator. 167/56

Now we divide 167 by 56 which is 2 and remainder is 55.
So, you should end up with a mixed fraction, 2 55/56.

7 0
3 years ago
Find the accumulated value of an investment of for years at an interest rate of if the money is a. compounded​ semiannually; b.
neonofarm [45]

Answer:

I dont know ask your mom or dad or sum to help u-

Step-by-step explanation:

3 0
3 years ago
Write the following expression with as few symbols as possible, using the notational conventions:
My name is Ann [436]

Answer:

The simplified expressions are (<em>x</em> + <em>y·</em>z' + <em>t</em>) and <em>x·</em>(<em>x</em> + <em>y</em>' + <em>z</em>) respectively.

Step-by-step explanation:

The expressions provided are:

(i)\ x+((y\times (z')) +t)\\\\(ii)\ x\times((x+(y'))+z)

(i)

Simplify the first expression with as few symbols as possible:

x+((y\times (z')) +t)=x+(yz'+t)

                              =x+yz'+t

(ii)

Simplify the second expression with as few symbols as possible:

x\times((x+(y'))+z)=x\times ((x+y')+z)

                              =x (x+y'+z)

Thus, the simplified expressions are (<em>x</em> + <em>y·</em>z' + <em>t</em>) and <em>x·</em>(<em>x</em> + <em>y</em>' + <em>z</em>) respectively.

6 0
3 years ago
For the function f(x)=ax^3+bx^2-5x+9, determine the values of a and b so that f(-1)=12 and f'(-1)=3
Alecsey [184]

If

<em>f(x)</em> = <em>ax</em> ³ + <em>bx</em> ² - 5<em>x</em> + 9

then

<em>f '(x)</em> = 3<em>ax </em>² + 2<em>bx</em> - 5

Given that <em>f</em> (-1) = 12 and <em>f</em> '(-1) = 3, we get the system of equations

-<em>a</em> + <em>b</em> + 5 + 9 = 12

3<em>a</em> - 2<em>b</em> - 5 = 3

or

-<em>a</em> + <em>b</em> = -2

3<em>a</em> - 2<em>b</em> = 8

Multiply through the first equation by 2 and add it to the second one to eliminate <em>b</em> and solve for <em>a</em> :

2(-<em>a</em> + <em>b</em>) + (3<em>a</em> - 2<em>b</em>) = 2(-2) + 8

-2<em>a</em> + 2<em>b</em> + 3<em>a</em> - 2<em>b</em> = -4 + 8

<em>a</em> = 4

Substitute this into the first equation above to solve for <em>b</em> :

-4 + <em>b</em> = -2

<em>b</em> = 2

4 0
3 years ago
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