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serious [3.7K]
3 years ago
12

Another fair dice is rolled 300 times. How many times would you expect it to land with a multiple of three on top? I need help t

his is a probability question. Show your work thanks.
Mathematics
1 answer:
ira [324]3 years ago
7 0

Answer:

100 times

Step-by-step explanation:

multiples of 3 on a number cube are 3 and 6

probability of rolling a '3' or '6' is 1/6 + 1/6 = 2/6 or 1/3

1/3 x 300 = 100

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Select all values of x that make the inequality −x+6≥10 true.
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3 years ago
According to the University of Nevada Center for Logistics Management, 6% of all merchandise sold in the United States gets retu
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Answer:

p_v =P(z>3.390)=0.000349  

If we compare the p value and the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the proportion of returns at the Houston store is significantly higher than 0.06 or 6%.

Step-by-step explanation:

1) Data given and notation n  

n=80 represent the random sample taken

X=12 represent number of items returned

\hat p=\frac{12}{80}=0.15 estimated proportion of items returned

p_o=0.06 is the value that we want to test

\alpha=0.1 represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that proportion of returns at the Houston store was more than the national expectation (0.06):  

Null hypothesis:p\leq 0.06  

Alternative hypothesis:p >0.06  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.15 -0.06}{\sqrt{\frac{0.06(1-0.06)}{80}}}=3.390  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.1. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>3.390)=0.000349  

If we compare the p value and the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the proportion of returns at the Houston store is significantly higher than 0.06 or 6%.

4 0
3 years ago
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