Pop ok you see so the answer here would be frantically elastic
The Solution:
Given:
Center = (0,0)
Point A = (-5,2) being a point on the circle.
We are required to check if point P = (2,-5) is on the circle.
Solving the given problem graphically, we have:
From the above graph, it is clear that point P(2,-5) is a point on the circle.
Answer:
Y=3x + 4
Step-by-step explanation:
Gradient = rise/run
=9/3
=3
Y-intercept is also 4
Answer:
4z - 15
4(3) - 15
12 - 15
= -3
High school math? really?