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earnstyle [38]
3 years ago
13

Solve 4x+2 = 12 for x using the change of base formula log base b of y equals log y over log b.

Mathematics
2 answers:
Arisa [49]3 years ago
8 0
The answer is 3.5
You can just stick with a 2 step equation method and it would work.
Oksana_A [137]3 years ago
4 0

Answer:

x=2.5

Step-by-step explanation:

We have,

4x+2=12

\implies4x=10

Taking log both the sides we have,  

log\,4x=log\,10

\implies log\,4 + log\,x=log\,10 \left\:\: [ \because log\,ab = log\, a + log\, b\right ]

\implies log\,x=log\,10 -log\,4

\implies log\,x={ log\,(\frac{10}{4}) \:\:\left [\because log\,a -log\,b= log\,\frac{a}{b} \right ]

\implies log\,x=log\,2.5

\implies \frac{log\,x}{log\,2.5}=1

\implies log_{(2.5)}\, x=1\:\:\left [ \because log_{b}\,a=\frac{log\,a}{log\,b} \right ]

\implies x=(2.5)^{1}\:\: [ \because log_{b}\,a=m \implies a=b^{m} ]

Hence, we have x=2.5

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oksian1 [2.3K]

part a: $37.60

idk part b

4 0
3 years ago
Assume that you have a sample of n 1 equals 6​, with the sample mean Upper X overbar 1 equals 50​, and a sample standard deviati
tigry1 [53]

Answer:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

df=6+5-2=9

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

n_1 =6 represent the sample size for group 1

n_2 =5 represent the sample size for group 2

\bar X_1 =50 represent the sample mean for the group 1

\bar X_2 =38 represent the sample mean for the group 2

s_1=7 represent the sample standard deviation for group 1

s_2=8 represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 > \mu_2

We are assuming that the population variances for each group are the same

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic for this case is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

The pooled variance is:

S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

We can find the pooled variance:

S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67

And the pooled deviation is:

S_p=7.46

The statistic is given by:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

The degrees of freedom are given by:

df=6+5-2=9

The p value is given by:

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0
3 years ago
Mark tosses a coin 25 times. What is the probability that it lands on heads exactly seven times?
mezya [45]

Answer:

1.43%

Step-by-step explanation:

we have that we can solve it by means of binomial, in this case m = 25. Also the probability of head is 50%. we need to know when it falls 7 times, therefore x = 7

the formula is:

P (x) = mCx * p ^ x * q ^ (m-x)

we know that p is 0.5 therefore q is equal to 0.5, replacing:

P (7) = 25C7 * 0.5 ^ 7 * 0.5 ^ (25-7)

P (7) = 25! / (7! * (25-7)!) * 0.5 ^ 7 * 0.5 ^ (25-7)

P = 0.0143

that is, the probability is 1.43%

6 0
3 years ago
Complete the comparison: 2+7>? a. 9+4 b. 7+3 c. 10-2 d. 8+2
Zina [86]
The answer is c because 2+7=9 and 10-2=8 and 9 is greater than 8 so 2+7>10-2
5 0
3 years ago
Help please.
FrozenT [24]

Answer:

B think

Step-by-step explanation:

4 0
3 years ago
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