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Citrus2011 [14]
3 years ago
13

900=400+789-680COS A

Mathematics
1 answer:
murzikaleks [220]3 years ago
8 0

Answer:

509cosa

Step-by-step explanation:

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In order to estimate the mean amount of time computer users spend on the internet each month. How many computer users must be su
evablogger [386]

Answer:

Step-by-step explanation:

Given that confidence level is 95% and sample mean is within 10 minutes of the population mean.  i.e. margin of error = 10

Std deviation of population= 211 minutes

Margin of error = Z critical * std error

Std error = sigma/sq rt n = \frac{211}{\sqrt{n} }

Hence we have

\frac{211}{\sqrt{n} }\frac{211}{\sqrt{n} }*1.9641.356\\n>1710

The minimum sample size is 1710

a) There may not be 1,809 computer users to survey

4 0
3 years ago
Plz help and I will give brainliest
DiKsa [7]

Answer:

a. f<g is one of them. On the number line, g is closest to 0, meaning it is greater than f.

b. h>0 is one answer. H is to the right of 0, meaning that h is greater than 0.

c. im sorry, i dont know.

Step-by-step explanation:

If this is graded, I hope you get a good grade!

4 0
3 years ago
2 5x2 - 19x + 12<br> Standard form
irina [24]

Answer:

5x 2 19x 4

9 6x 2 19x 2

factor 5x 2 19x 4

4x 2 19x 5 0

factor 6x 2 19x 7

6x 2 19x 36Factor 5x^2-19x+12. For a polynomial of the form , rewrite the middle term as a sum of two terms whose product is and whose sum is . Tap for more steps... Factor out of . Rewrite as plus. Apply the distributive property. Factor out the greatest common factor from each group. Tap for more steps...

Step-by-step explanation:

5 0
3 years ago
A polynomial function with a leading coefficient of 1 and multiplicity 1 for each root has these zeros:
Gala2k [10]

Answer:

1.

x - 2 \sqrt{11}

2.

x + 2 \sqrt{11}

5.

x - 4

Step-by-step explanation:

It is correct on Edge!

Give thanks please!

6 0
3 years ago
Plz help me ill give brainly
Dafna11 [192]

Answer:

3.6 divided by 3 = 1.2 so 1.2 yards of material can be used on each skirt.

Step-by-step explanation:

4 0
3 years ago
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