The confidence interval for the mean usage of water is (18.7,20.5).
Given population standard deviation of 2.4, mean of 19.5 gallons per day and confidence interval of 98%.
We have to find the confidence interval for the mean usage of water.
To find out the confidence interval we have to first find margin of error.
μ=19.5
σ=2.4
α=0.98
α/2=0.49
We have to find the z value for the p value 0.49 which is z=2.33
Margin of error=z*μ/
=2.33*19.5/
=0.82
lower level=mean -m
=19.5-0.82
=18.68
after rounding upto 1 decimal
=18.7
upper mean = mean+m
=19.5+0.82
=20.52
Hence the confidence interval for the usage of water is (18.7,20.52).
Learn more about margin of error at brainly.com/question/10218601
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Good luck, I am not sure how to solve the next part of the question
Answer: 480 units^2
IN DEPTH EXPLANATION TO HELP YOU FOR FUTURE PROBLEMS:
Front:
b*h/2 = sa
12*5/2 = 30
Front = 30 units^2
Back:
b*h/2 = sa
12*5/2 = 30
Back = 30 units^2
Right:
w*l = sa
14*13 = 182 units^2
Right: 182 units*2
(figures out the length by using
pythagorean theorem)
Left:
w*l = sa
5*14 = 70 units^2
Left: 70 units^2
Bottom:
w*l = sa
12*14 = 168 units^2
ADD ALL THE UNITS:
168 + 70 + 182 + 30 + 30 = 480
Answer:
6d+49.8
If looking for d=8.316 but 6 is repeated
Step-by-step explanation:
Answer: half year
Step-by-step explanation:
The formula to find the simple interest is given by :-
, , where P is the principal amount , r is the rate of interest and t is the time in year.
Given : I=420 ; r=14%=0.14 and P =$6000
Then, we have the following equation :-
It means the duration of the loan is half year .
