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4 years ago

HELP FAST. 40 points A. ABCD B. BCDA C. CDAB D. DABC

Mathematics

1 answer:

Natali5045456 [20]4 years ago

7 0

Based on the table, Problem A needs to be fixed in 24 hours (9 AM tomorrow). Problem B needs to be fixed in 24 hours (10 AM tomorrow). Problem C needs to be fixed in 12 hours (11 PM that night). Problem D needs to be fixed in 12 hours (11:30 PM that night). So the technician's order will be: C, D, A, B. This is the third choice.

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Write an exponential function that passes through the points (0, 3) and (-1, 6)

FinnZ [79.3K]

Standard form of an exponential function is y=ab^x
when x=0, y=3, 3=ab^0, so you can figure out that a=3
when x=-1, y=6, 6=3b^(-1), b^(-1)=2, b=1/2
so the equation is y=3(1/2)^x

3 0

3 years ago

Given the functions: g(n) = 3n - 5 f(n) = n2 + 50 Find: (g+f)(8)

puteri [66]

Answer:

$(g + f)(8) =133$

Step-by-step explanation:

Given

$g(n) = 3n - 5$

$f(n) = n^2 + 50$

Required

$(g + f)(8)$

This is calculated as:

$(g + f)(n) =g(n) + f(n)$

So, we have:

$(g + f)(n) =3n - 5 + n^2 +50$

$Substitute$ 8 for n

$(g + f)(8) =3*8 - 5 + 8^2 +50$

$(g + f)(8) =24 - 5 + 64 +50$

$(g + f)(8) =133$

7 0

3 years ago

What is the value of the product (3-2i)(3+2i)?

Helga [31]

Answer:

Step-by-step explanation:

(3-2i)(3+2i) = 9 + 6i - 6i - 4i^2

9 - 4i^2

9 + 4 = 13

5 0

4 years ago

Read 2 more answers

[{ (-3-7) + 4 x 5} x 5 + 10 ] / -12 solve this on a paper a send a photo please

Natali5045456 [20]

Answer:

Step-by-step explanation:

ITS 5

8 0

3 years ago

Please help with this asappppppppll

Alenkinab [10]

We are given with a circle and we need to find the equation of the circle , but first let's recall that , the equation of a circle with radius 'r' and centre at (h,k) is given by ${\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}}$

Now , here as as the circle cuts the +ve x-axis at (9,0) . So , it's radius is 9 units or the 2nd way is to measure the distance from centre of the circle to the point where the circle cuts the graph , as the centre is at Origin , so here (h,k) = (0,0) .Which means that the centre is located at the point whose coordinates are (0,0) which is also known as origin . Now , finding the equation of the circle :-

${:\implies \quad \sf (x-0)^{2}+(y-0)^{2}=(9)^{2}}$

${:\implies \quad \bf \therefore \quad \underline{\underline{x^{2}+y^{2}=81}}}$

This is the required equation of Circle

7 0

3 years ago