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stepan [7]
3 years ago
10

HELP FAST. 40 points A. ABCD B. BCDA C. CDAB D. DABC

Mathematics
1 answer:
Natali5045456 [20]3 years ago
7 0
Based on the table, Problem A needs to be fixed in 24 hours (9 AM tomorrow). Problem B needs to be fixed in 24 hours (10 AM tomorrow). Problem C needs to be fixed in 12 hours (11 PM that night). Problem D needs to be fixed in 12 hours (11:30 PM that night). So the technician's order will be: C, D, A, B. This is the third choice.
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Monica is a lawyer who earns $8,322.65 every month. She spends $830.98 on rent, $210.36 on food, and $120.45 on gas every month.
dolphi86 [110]

Answer:

Money left from her earning after expenses is $ 7160.86

Step-by-step explanation:

Money earned by Monica every month = $ 8322.65

Money spend on rent = $ 830.98

Money spend on food = $ 210.36

Money spend on gas every month = $ 120.45

Money left from her earning = 8322.65 - ( 830.98 + 210.36 + 120.45 )

                                              = 8322.65 - 1161.79

                                              = $ 7160.86

3 0
3 years ago
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Solve P = P - C for C
Rina8888 [55]

Answer:

c=0

Step-by-step explanation:

5 0
3 years ago
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Compound interest earns interest on both the principal and the interest already earned.
kow [346]

Answer:

Step-by-step explanation:

Pretty sure its true but im a little iffy

5 0
3 years ago
Suppose a football is kicked with an initial velocity of 82 ft/sec., at an angle of
satela [25.4K]

Answer:

The position P is:

P = 87\^x + 75\^y ft     <u><em> Remember that the position is a vector. Observe the attached image</em></u>

Step-by-step explanation:

The equation that describes the height as a function of time of an object that moves in a parabolic trajectory with an initial velocity s_0 is:

y(t) = y_0 + s_0t -16t ^ 2

Where y_0 is the initial height = 0 for this case

We know that the initial velocity is:

82 ft/sec at an angle of 58 ° with respect to the ground.

So:

s_0 = 82sin(58\°) ft/sec

s_0 = 69.54 ft/sec

Thus

y(t) = 69.54t -16t ^ 2

The height after 2 sec is:

y(2) = 69.54 (2) -16 (2) ^ 2

y(2) = 75\ ft

Then the equation that describes the horizontal position of the ball is

X(t) = X_0 + s_0t

Where

X_ 0 = 0 for this case

s_0 = 82cos(58\°) ft / sec

s_0 = 43.45 ft/sec

So

X(t) = 43.45t

After 2 seconds the horizontal distance reached by the ball is:

X (2) = 43.45(2)\\\\X (2) = 87\ ft

Finally the vector position P is:

P = 87\^x + 75\^y ft

6 0
3 years ago
Jerome used 3 and 1/4 gallons of gasoline while driving from school to to his baseball game. If he originally had 7 gallons in h
kozerog [31]
7 - 3 1/4 = (turn mixed number to improper fraction
7 - 13/4 = (common denominator is 4)
28/4 - 13/4 =
15/4 or 3 3/4 gallons remain in the tank

6 0
3 years ago
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