We use letters to represent the unknown coins. P for pennies that worth 1 cents N for nickels that worth 5 cents D for dimes that worth 10 cents Q for quarters that worth 25 cents.
<span>"He has twice as many nickels (N) as dimes (D)" So D=2N </span><span>"and four times as many pennies (P) as quarters (Q)." So Q=4P </span> Number of coins equals P+N+D+Q=P+N+2N+4P (Dimes and quarters are written in terms of nickels and pennies, respectively)
So, number of coins is equal to 5P+3N=201. Thats is the first equation (I) To write the second equation, use cents of coins. 12.10 $ in coins can be shown as
We have two equations and two unknowns so it is soluble. number of coins: 5P+3N=201 (I) cents of coins: 5P+15N=1210 (II) Use the substitution method. (II) - (I)=12N=1009 N=1009/12=84 ( Actually it is 84.08) D=2N=168 P= -10 Q=-40 Number of pennies and quarters are <span>meaningless. They can't be negative. So they should be something wrong in the question.</span>
<span><span><span>x = ± 2</span></span><span><span>Then the solution is </span><span>x = ± 2</span></span><span><span>hope this helps</span></span></span>
