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andrezito [222]
3 years ago
10

Regular hexagon ABCDEF is inscribed in a circle with center H. What is the image of segment BC after 120 degree clockwise rotati

on about point H?

Mathematics
1 answer:
fiasKO [112]3 years ago
4 0

Answer: The answer would be EF

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A number , x, decreased by the sum of 4x and 6
Andru [333]

Answer:

-3x - 6

Step-by-step explanation:

x - (4x + 6) becomes x - 4x - 6 after we've distributed the multiplication.

We can simplify this result as follows:  -3x - 6

3 0
3 years ago
The quadrilateral is a <br> (A)Rhombus <br> (B)Square <br> (C)rectangle <br> (D)parallelogram
Verizon [17]

Answer:

A) Rhombus

Step-by-step explanation:

3 0
2 years ago
An article presents a new method for timing traffic signals in heavily traveled intersections. The effectiveness of the new meth
Anna35 [415]

Answer:

With 89.9% we can say that the mean improvement is between 583.1 and 728.1 vehicles per hour.

Step-by-step explanation:

We are given that the effectiveness of the new method was evaluated in a simulation study. In 50 simulations, the mean improvement in traffic flow in a particular intersection was 655.6 vehicles per hour, with a standard deviation of 311.7 vehicles per hour.

A traffic engineer states that the mean improvement is between 583.1 and 728.1 vehicles per hour.

<em>Let </em>\bar X<em> = sample mean improvement</em>

The z-score probability distribution for sample mean is given by;

            Z =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = mean improvement = 655.6 vehicles per hour

            \sigma = standard deviation = 311.7 vehicles per hour

            n = sample of simulations = 50

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the mean improvement is between 583.1 and 728.1 vehicles per hour is given by = P(583.1 < \bar X < 728.1) = P(\bar X < 728.1) - P(\bar X \leq 583.1)

  P(\bar X < 728.1) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{728.1-655.6}{\frac{311.7}{\sqrt{50} } } ) = P(Z < 1.64) = 0.9495

  P(\bar X \leq 583.1) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \leq \frac{583.1-655.6}{\frac{311.7}{\sqrt{50} } } ) = P(Z \leq -1.64) = 1 - P(Z < 1.64)

                                                            = 1 - 0.9495 = 0.0505                      

<em />

<em>So, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1.64 in the z table which has an area of 0.9495.</em>

Therefore, P(583.1 < \bar X < 728.1) = 0.9495 - 0.0505 = 0.899 or 89.9%

Hence, with 89.9% we can say that the mean improvement is between 583.1 and 728.1 vehicles per hour.

6 0
3 years ago
Find AC and BC. <br><br> Answers: <br> 14.94<br> 13.46<br> 11.10<br> 10<br> Please help.
anzhelika [568]

Step-by-step explanation:

Use Sine rule.

\frac{ac}{ \sin(b) }  =  \frac{ab}{ \sin(c) }  \\  \frac{ac}{ \sin(90) } =  \frac{10}{ \sin(42) }   \\  ac \sin(42)  = 10 \sin(90)  \\ ac =  \frac{10 \sin(90) }{ \sin(42) }  \\  ac = 14.9 \: units \: (3s.f)

Angle A + angle B + angle C = 180 (sum of angles in triangle)

Angle A + 90 + 42 = 180

Angle A + 132 = 180

Angle A = 180 - 132

= 48

\frac{bc}{ \sin(a) }  =  \frac{ab}{ \sin(c) }  \\  \frac{bc}{ \sin(48) } =  \frac{10}{ \sin(42) }   \\  bc \sin(42)  = 10 \sin(48)  \\ bc =  \frac{10 \sin(48) }{ \sin(42) }  \\  = 11.1units (3sf)

3 0
3 years ago
Pls help!! person with correct answer will be marked brainliest!!
bezimeni [28]

Answer:

119 degrees

Step-by-step explanation:

180 degrees - 61 degrees  = 119 degrees

4 0
3 years ago
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