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Answer:
T₂ = 43.46 °C
Explanation:
Given that:
The heat of the formation of carbon dioxide = - 393.5 kJ/mol (Negative sign suggests heat loss)
It means that energy released when 1 mole of carbon undergoes combustion = 393.5 kJ = 393500 J
Heat gain by water = Heat lost by the reaction
Thus,
For water:
Mass of water = 5100 g
Specific heat of water = 4.18 J/g°C
T₁ = 25 °C
T₂ = ?
Q = 393500 J
So,
T₂ = 43.46 °C
Answer: The time is 0.69/k seconds
Explanation:
The following integrated first order rate law
ln[SO₂Cl₂] - ln[SO₂Cl₂]₀ = - k×t
where
[SO₂Cl₂] concentration at time t,
[SO₂Cl₂]₀ initial concentration,
k rate constant
Therefore, the time elapsed after a certain concentration variation is given by:
We could assume that SO₂Cl₂ behaves as a ideal gas mixture so partial pressure is proportional to concentration:
In conclusion,
t = ln( p(SO₂Cl₂)₀/p(SO₂Cl₂) )/k
for