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kupik [55]
3 years ago
11

What are the zeros of the polynomial equation f(x)=x^2-12x+20?

Mathematics
1 answer:
bagirrra123 [75]3 years ago
8 0
f(x)=x^2-12x+20\\\\\text{The zeros:}\\\\f(x)=0\to x^2-12x+20=0\\\\x^2-10x-2x+20=0\\\\x(x-10)-2(x-10)=0\\\\(x-10)(x-2)=0\iff x-10=0\ \vee\ x-2=0\\\\\boxed{x=10\ \vee\ x=2}
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Answer:

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Step-by-step explanation:

We have given expression and we have to simplify the expression using exponent property

(A) (\frac{1}{e})^{-2}

So (\frac{1}{e})^{-2}=\frac{1}{e^{-2}}=e^2

(b) (\frac{e^5}{e^2})^{-1}

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