3 years ago

What are the zeros of the polynomial equation f(x)=x^2-12x+20?

1 answer:

8 0

$f(x)=x^2-12x+20\\\\\text{The zeros:}\\\\f(x)=0\to x^2-12x+20=0\\\\x^2-10x-2x+20=0\\\\x(x-10)-2(x-10)=0\\\\(x-10)(x-2)=0\iff x-10=0\ \vee\ x-2=0\\\\\boxed{x=10\ \vee\ x=2}$

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Answer:

Cheryl is correct.

Step-by-step explanation:

Cheryl solved a problem : 84 ÷ 0.01 = 8,400.

This is absolutely right.

When we divide any whole number with the divisor having decimal, we change the divisor to a whole number before performing the division.

To do this, we multiply both the numbers (divisor and dividend) by the same power of 10, until the divisor is a whole number.

$\frac{84\times 10}{0.01\times 10}$ = $\frac{840}{0.1}$

to make divisor a whole number we will again multiply both the numbers by 10.

$\frac{840\times 10}{0.1\times 10}$ = $\frac{8400}{1}$ = 8,400

Now answer would be 8400.

Therefore, Cheryl is correct.

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