What is the coefficient of determination for this data set?

What's the slope of the line ? And explain please

tia_tia [17]

You take the difference between any two y and divide by the difference in the corresponding x. The number should be the same always for a straight line. That's your slope. A fancy way of writing it is dy/dx

so: (10-2)/(3-1) = 8/2 = 4 (using the first two points)
or: (26-2)/(7-1) = 24/6 = 4 (using the first and the last)

try it out for other combinations. The answer is 4 every time.

5 0

3 years ago

Solve mathematics question, please:) Unanswered re-asked question.

Fiesta28 [93]

Remember you can do anything to an equation as long as you do it to both sides

and when multiply by negative, flip sign

8+h>2+3h
minus h both sides
8+h-h>2+3h-h
8+0>2+2h
8>2+2h
minus 2 both sides
8-2>2-2+2h
6>0+2h
6>2h
divide by 2 both sides
6/2>2h/2
3>1h
3>h

first opotin

3 0

3 years ago

Read 2 more answers

today Kylee put a kitchen table on layaway by making a down payment of 120 and agreeing to pay $48 a month starting next month f

yawa3891 [41]

Answer:

2 1/2 months by the 3rd month

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

55% of 19.6 is what number?

tiny-mole [99]

10.78 is the answer.
19.6 x .55

3 0

3 years ago

According to the Vivino website, suppose the mean price for a bottle of red wine that scores 4.0 or higher on the Vivino Rating

Natali [406]

Answer:

a) Null and alternative hypothesis

$H_0: \mu=32.48\\\\H_a:\mu< 32.48$

b) Test statistic t=-1.565

P-value = 0.0612

NOTE: the sample size is n=65.

c) Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

d) Null and alternative hypothesis

$H_0: \mu=32.48\\\\H_a:\mu< 32.48$

Test statistic t=-1.565

Critical value tc=-1.669

t>tc --> Do not reject H0

Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

Then, the null and alternative hypothesis are:

$H_0: \mu=32.48\\\\H_a:\mu< 32.48$

The significance level is 0.05.

The sample has a size n=65.

The sample mean is M=30.15.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=12.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{12}{\sqrt{65}}=1.4884$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{30.15-32.48}{1.4884}=\dfrac{-2.33}{1.4884}=-1.565$

The degrees of freedom for this sample size are:

$df=n-1=65-1=64$

This test is a left-tailed test, with 64 degrees of freedom and t=-1.565, so the P-value for this test is calculated as (using a t-table):

$\text{P-value}=P(t$

As the P-value (0.0612) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

At a significance level of 0.05, there is not enough evidence to support the claim that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

<u>Critical value approach</u>

<u></u>

At a significance level of 0.05, for a left-tailed test, with 64 degrees of freedom, the critical value is t=-1.669.

As the test statistic is greater than the critical value, it falls in the acceptance region.

The null hypothesis failed to be rejected.

6 0

2 years ago