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3 years ago

The possible results of an experiment are called its

Mathematics

1 answer:

Blizzard [7]3 years ago

4 0

Theoretical probability is determined through a study of the possible outcomes that can occur for the given experiment.

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Can someone help me please and thank you!!

Ipatiy [6.2K]

Answer:

Perimeter: perimeter = (12 x 2) + (x-2 times 2)

Area: 12 x (x-2)

Step-by-step explanation:

I hope im right im only in grade 6 so wouldnt trust me with that :/

6 0

3 years ago

Which function has the same y-intercept as the function y equals 2/3 x - 3

aleksley [76]

We have the function $y = \frac{2}{3} x -3$ and we want to find a function that has the same y-intercept than the previous function.

First, let's find the y-intercept by subtituting 0 for 'x'.

$y = \frac{2}{3} (0) -3 = -3$

Now that we found that y-intercept =-3, any lineal function of the type: $y = ax - 3$ will have the same y-intercept. Where 'a' can take all the real values.

Also, any quadratic function of the type: $y=ax^{2} + bx - 3$ will have the same y-intercept. Where 'a' and 'b' can take all the real values.

6 0

3 years ago

Rhianna has £25 to spend on plants.

frosja888 [35]

Answer:

£0.33

Step-by-step explanation:

Rhianna has £25.

1 plant costs £3.95, she buys all of them.

25/3.95 = 6.329114

She buys a total of 6 plants.

With £0.33 remaining, which is the change.

7 0

3 years ago

Read 2 more answers

What is the answer please

vovikov84 [41]

Answer:

2/3

Step-by-step explanation:

2/3 is the answer mark me the brainliest

4 0

3 years ago

Can you please help me out

Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

$\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}$

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

$\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}$ $\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}$

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

$\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}$

Hence, the best option is G.

5 0

1 year ago