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3 years ago

Work out. 2/11 + 3/5

Mathematics

2 answers:

iren2701 [21]3 years ago

5 0

Answer:

43/55

Step-by-step explanation:

Helen [10]3 years ago

3 0

.781111111 repeating. or 43/55

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Which pair of slopes show that line AD is perpendicular to line BC?

grigory [225]

Answer:

7,1/7

Step-by-step explanation:

6 0

2 years ago

Consider three persons, A, B, and C, who are to be seated in a row of three chairs. Suppose A and B are identical twins. How man

zubka84 [21]

Answer:

2 ways

Step-by-step explanation:

The best way to do this is to fix the position of the stranger and then arrange the two identical twins

The number of ways of knowing where the stranger will seat is 1! ways = 1 way

The number of ways of arranging the two identical twins is 2! ways = 2*1 = 2 ways

The number of sitting arrangements = 1 * 2 = 2 ways

6 0

3 years ago

exis [7]

Answer:

Part 1) The length of the longest side of ∆ABC is 4 units

Part 2) The ratio of the area of ∆ABC to the area of ∆DEF is $\frac{1}{100}$

Step-by-step explanation:

Part 1) Find the length of the longest side of ∆ABC

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

The ratio of its perimeters is equal to the scale factor

Let

z ----> the scale factor

x ----> the length of the longest side of ∆ABC

y ----> the length of the longest side of ∆DEF

$z=\frac{x}{y}$

we have

$z=\frac{1}{10}$

$y=40\ units$

substitute

$\frac{1}{10}=\frac{x}{40}$

solve for x

$x=(40)\frac{1}{10}$

$x=4\ units$

therefore

The length of the longest side of ∆ABC is 4 units

Part 2) Find the ratio of the area of ∆ABC to the area of ∆DEF

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z ----> the scale factor

x ----> the area of ∆ABC

y ----> the area of ∆DEF

$z^{2}=\frac{x}{y}$

we have

$z=\frac{1}{10}$

$z^2=(\frac{1}{10})^2$

$z^2=\frac{1}{100}$

therefore

The ratio of the area of ∆ABC to the area of ∆DEF is $\frac{1}{100}$

3 0

2 years ago

What is the slope of the line of (1,0) and (-1,-3)

Alinara [238K]

Slope formula: m = $\frac{(y2-y1)}{(x2-x1)}$ (Knowing that m represents the slope)

Substitute (1,0) for (x1,y1), and (-1,-3) for (x2,y2)

Slope of the line of (1,0) and (-1,-3) is:

m = $\frac{(-3-0)}{(-1-1)}$ = $\frac{-3}{-2}$ = $\frac{3}{2}$

(Simplify)

Slope of the line of (1,0) and (-1,-3) is $\frac{3}{2}$

6 0

3 years ago

What is the slope of the line that passes through the points e(-1,4) and f(2,6)?

Marysya12 [62]

(-1,4)(2,6)
slope = (6 - 4) / (2 - (-1) = 2 / (2 + 1) = 2/3 <==

4 0

3 years ago