X^2+y^2 = 16
can be written as
(x-0)^2+(y-0)^2 = 4^2
We see that the second equation is in the form
(x-h)^2 + (y-k)^2 = r^2
where
(h,k) = (0,0) is the center
r = 4 is the radius
The polar form of the equation is simply r = 4. Why is this? Because the radius is fixed to be 4 no matter what happens with theta. As theta goes from 0 to 360, the points generated all form a circle centered at (0,0) with radius 4.
Answer: r = 4
Answer: There you go, hope it helps!
Step-by-step explanation:
Okay,not sure if this is what you're looking for but hope this helps :)
When the y variable tends to increase as the x variable increases, we say there is a positive correlation between the variables. When the y variable tends to decrease as the x variable increases, we say there is a negative correlation between the variables
Answer: it gets smaller, 13 times smaller
Step-by-step explanation:
Size of the figure/13
Answer:
A
Step-by-step explanation:
For point-slope form, you need a point and the slope.
y - y₁ = m(x - x₁)
Looking at the graph, the points you have are (4, 0) and (-4, -4). You can use these points to find the slope. Divide the difference of the y's by the difference of the x's/
-4 - 0 = -4
-4 - 4 = -8
-4/-8 = 1/2
The slope is 1/2. This cancels out choices C and D.
With the point (-4, -4), A is the answer.
-1 (-12 - 9i) + 4i (-12 - 9i)
= 12 + 9i + -48i + 9i^2
= 9i^2 + 39i + 12