1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
elixir [45]
3 years ago
6

Rewrite 0.6+(-1)-(-0.8)-0.4=0

Mathematics
1 answer:
maria [59]3 years ago
7 0

Answer:

LHS = RHS

Step-by-step explanation:

Given: 0.6 + (-1) - (- 0. 8) - 0. 4 = 0

RHS = 0

We will compute LHS now.

We can re write the question as follows:

= 0. 6 - 1 + 0. 8 - 0. 4

We use BODMAS (Bracket, Of, Division, Multiplication, Addition, Subtraction) to solve further.

So, we add the terms first.

= 0. 6 + 0. 8 - 1 - 0. 4

= 1 . 4 - (1 + 0. 4)

= 1. 4 - 1 . 4

= 0

∴ LHS = 0

This matches with the given question.

LHS = RHS

You might be interested in
Ram has three times as many Rupees to coins as he has rupees 5 coins if he has in all a sum of rupees 77 how many coins of Rupee
BabaBlast [244]

9514 1404 393

Answer:

  21 coins of ₹2

Step-by-step explanation:

Let x represent the number of ₹2 coins, and y the number of ₹5 coins. Then the total value of the coins is ...

  2x +5y = 77

and the relationship between numbers of coins is ...

  x = 3y

Substituting for x, we have ...

  2(3y) +5y = 77

  y = 77/11 = 7 . . . . simplify, divide by the coefficient of y

  x = 3(7) = 21 . . . . find x from the second equation

Ram has 21 of the ₹2 coins.

8 0
2 years ago
Make x the subject of m=n + x/p
marshall27 [118]

Answer:

\boxed{x = p(m - n)}

Step-by-step explanation:

=  > m = n +  \frac{x}{p}  \\  \\  =  > m = (n \times  \frac{p}{p} ) +  \frac{x}{p}  \\  \\  =  > m =  \frac{pn}{p}  +  \frac{x}{p}  \\  \\  =  > m =  \frac{pn + x}{p}  \\  \\  =  > mp = pn + x \\  \\  =  > x + pn = pm \\  \\  =  > x = pm - pn \\  \\  =  > x = p(m - n)

4 0
3 years ago
14,2,7,3,9 =10 I need help
Misha Larkins [42]

Answer: 7+3 =10

Step-by-step explanation: Those were the only two numbers added or subtracted together that I found made 10. I hope this helps :).

7 0
1 year ago
Two fractions are given. For each one, write its decimal equivalent and determine if the decimal is terminating or non terminati
ziro4ka [17]

Answer:

9/20 yes, 4/15 not. See below

Step-by-step explanation:

Pick 9/20 and multiply numerator and denominator by 5:

9/20 = 45/100

We know that if we divide a number by 100 we need to move the coma as two places left, so:

9/20 = 45/100 = 0.45

And this is a terminal decimal as we know where it ends.

On the other hand if we pick 4/15 let try to divide it (here I will do it 'manually'):

4 |_ 15

we can divide 4 by 15, so we use 40 and begin with a comma

40 |_ 15

      0.

15 enters 2 times in 40 with a rest of 10, so:

40 |_ 15

  30  0.2

  100

100 divided by 15 is 6 and we have 10 as rest again, and again and again...

40 |_ 15

  30  0.266.....

  100

    100

      ....

So, we will have 0.266666666666666 infinitely. The decimal for 4/15 is non terminating and is 0.26666666666666666...

6 0
3 years ago
Which value is NOT a solution of 8x3 – 1 = 0?
Tpy6a [65]

<u><em>Note: As you may have unintentionally missed to add the value choices. But, I would make sure to explain the concept so that you may improve your understanding in terms of solving these type of questions.</em></u>

Answer:

Any value other than the values x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4} will not be a solution of 8x^3\:-\:1\:=\:0.

Step-by-step explanation:

Considering the equation

8x^3\:-\:1\:=\:0

Steps to solve the equation

8x^3-1=0

\mathrm{Add\:}1\mathrm{\:to\:both\:sides}

8x^3-1+1=0+1

\mathrm{Simplify}

x^3=\frac{1}{8}

\mathrm{Divide\:both\:sides\:by\:}8

\frac{8x^3}{8}=\frac{1}{8}

\mathrm{Simplify}

x^3=\frac{1}{8}

As

\mathrm{For\:}x^3=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}

x=\sqrt[3]{\frac{1}{8}},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1+\sqrt{3}i}{2},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1-\sqrt{3}i}{2}

So,

x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}

Therefore,

Any value other than the values x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4} will not be a solution of 8x^3\:-\:1\:=\:0.

Keywords: solution, value

Learn more about equation solution from  brainly.com/question/1679491

#learnwithBrainly

7 0
2 years ago
Other questions:
  • What is the lengh of de?
    13·1 answer
  • What is the value of 2/5x3/5
    15·2 answers
  • I do not know how to work this out... can someone PLEASE help me???
    9·2 answers
  • 3a +6b in distributed property
    5·1 answer
  • A smog alert has been called in a certain area of Los Angeles County in which there are 50 industrial rms. An inspector will vis
    9·1 answer
  • Can yall please help me ??
    8·1 answer
  • For a class of 25 students, 5 pizzas are needed for
    15·1 answer
  • Your friend says that 14.5% is equivilent to 14.5
    7·2 answers
  • I know it’s not a lot of points but I need help
    14·1 answer
  • The results of 11 students in a test are:4,19,7,18,15,9,17,14,10,13,11. what is the median.​
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!