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lubasha [3.4K]
3 years ago
15

ms.morgan is a science teacher. she founs that 30% of her 120 students are athletes. mr. gregory is a math teacher. he found out

that 27 or 15% of his students are athletes. of the part,the whole, and the percent, which information is still unknown to mr.gregory?find this unknown value.
Mathematics
1 answer:
Readme [11.4K]3 years ago
7 0

Answer:

Huh? Spell it better. Try copy and paste.

Step-by-step explanation:

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Find the area. HELP PLEASE!!!!!!​
kaheart [24]

Answer:

616

Step-by-step explanation:

The equation to find the area of a trapezoid is:  A = ½ (b^1+b²) h.

b1=43

b2=45

h=14

Plug the variables in and solve.

A=\frac{1}{2} (43+45)14

A=\frac{1}{2} (88)14

A=\frac{1}{2} (1232)

A=616

3 0
2 years ago
Read 2 more answers
X+4y=4 y in terms of x
Alinara [238K]

Answer:

x + 4y = 4

4y = 4 - x

multiply both sides by 1/4

y = 1/4( 4- x)

y = 1- 1/4x

3 0
2 years ago
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PLEASE ANSWER 14 points!!!!
katen-ka-za [31]

Answer:

5

Step-by-step explanation:

sqrt[(-8+3)² + (-6+6)²] = 5

4 0
3 years ago
The faces on a number cube are labled 1,2,2,3,4, and 5the number cube is rolled 114 times how many times would you expect the nu
Mrac [35]

Given:

The faces on a number cube are labeled 1,2,2,3,4, and 5.

The number cube is rolled 114 times.

To find:

How many times would you expect the number 2 to appear?

Solution:

We have,

Total outcomes = 1,2,2,3,4, and 5.

Number of total outcomes = 6

Favorable outcomes = 2 and 2

Number of favorable outcomes = 2

The probability of getting 2 is:

P(2)=\dfrac{\text{Number of favorable outcomes}}{\text{Number of total outcomes}}

P(2)=\dfrac{2}{6}

P(2)=\dfrac{1}{3}

Now, the expected number of times when 2 to appear is:

E(x)=114\times P(2)

E(x)=114\times \dfrac{1}{3}

E(x)=38

Therefore, the expected number of times is 38.

4 0
2 years ago
Find a vector 3 units long in the opposite direction from v = 〈3, 1,-4).
lutik1710 [3]

Unit vector along the direction v = <3,1,-4> is :

\hat{v} = \dfrac{3i + j  -4k}{\sqrt{3^2 + 1^2 + 4^2}}\\\\\hat{v} = \dfrac{3i + j -4k}{5.1}

So, unit vector opposing the \hat{v} is :

\hat{v'} = -\hat{v}\\\\\hat{v'} = -( \dfrac{3i + j -4k}{5.1})\\\\\hat{v'} = \dfrac{-3i - j +4k}{5.1}

so, vector of magnitude 3 units in opposite direction from v is :

\vec{V} = 3\hat{v'}\\\\\vec{V} = \dfrac{3}{5.1}( -3i -j+4k)

Hence, this is the required solution.

5 0
3 years ago
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