Answer:
1/36
Step-by-step explanation:
When the coefficient is 1, the function has zeros at -3 and -5, one horizontal unit from the vertex. You want to move the zero to (2, 0), which is 6 units from the vertex. To achieve a horizontal stretch by a factor of 6, the value of x in the function must be replaced by x/6. That would make the coefficient of x^2 be (1/6)^2 = 1/36.
The coefficient of the squared term is 1/36.
The answer to this problem is 555.4
Answer:
2√13
Step-by-step explanation:
using the distance formula;
d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}
you plug the numbers in. once done you get 2√13.
Hope it helps!