Question

The areas of two circles are 36(pi) and 64(pi). What is hte ratio of the diameters? of the circumferences?

Answer 1

<u />$A_1=36\pi\ \ \ \Rightarrow\ \ \ \pi r ^2=36\pi\ \ \ \Rightarrow\ \ \ r^2=36\ \ \Rightarrow\ \ r=6\\ \\A_2=64\pi\ \ \ \Rightarrow\ \ \ \pi R ^2=64\pi\ \ \Rightarrow\ \ R^2=64\ \ \ \Rightarrow\ \ R=8 \\\\\\ \frac{2r}{2R} = \frac{r}{R} =\frac{6}{8}= \frac{3}{4}\ \ \ \ \ \ \ \ and\ \ \ \ \ \ \ \ \frac{2\pi r}{2\pi R} =\frac{r}{R} = \frac{3}{4}$

Answer 2

2,304 because if you multiply 36 x 64 is 2,304 if not multiply 2,304 x 36 x 64 and then divide the answer by 36 & 64 the it should be 2,304