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2 years ago

Hi i need help on this

Mathematics

2 answers:

disa [49]2 years ago

5 0

Answer:

x = 125

Step-by-step explanation:

Hope this helps! :)

Allushta [10]2 years ago

3 0

Answer
X=125
Solution
25x 4/25>25x5

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If the scale factor of a scale drawing is greater than one, the scale drawing is larger than the actual object

galina1969 [7]

False, for example, if the scale factor is 2, the scale drawing would still be smaller because it would be twice as smaller than the actual object.

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3 years ago

Triangle ABC has a perimeter 22cm AB = 8cm BC =8cm By calculation, deduce whether triangle ABC is a right angle triangle. NEED A

Likurg_2 [28]

Answer:

No ABC is not a triangle

Step-by-step explanation:

Perimeter = 22 cm

AB = 8 cm ; BC = 8 cm

AC = 22 - ( 8 + 8 ) = 6 cm

But all those sides doesn't follow Pythagorean Theorem(AB^2 + BC^2 = AC^2) ....because 8^2 + 8^2 isn't equal to 6^2 ......

Had it followed the theorem , it could have been a right angle triangle...

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3 years ago

I really need help on my algebra review

Ilya [14]

Answer:

the slope becomes 3 and the graph moves up 7 units. 2. The slope becomes 5 and the graph moves down 2 units.

]

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2 years ago

Three consecutive integers have a sum of 42. find the integers.

ioda

The answer is 13,14,15.

6 0

2 years ago

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

2 years ago