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Stella [2.4K]
2 years ago
9

Write down the solution to the simultaneous equations.

Mathematics
1 answer:
julia-pushkina [17]2 years ago
4 0

Answer:

x = 5/2; y = 7

Step-by-step explanation:

2x + y = 12

y = 2x + 2

Use substitution to replace y in the first equation with 2x + 2.

2x + 2x + 2 = 12

4x + 2 = 12

4x = 10

x = 10/4

x = 5/2

y = 2x + 2

y = 2(5/2) + 2 = 5 + 2

y = 7

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Answer:

"I can find the maximum or minimum by looking at the factored expression of a quadratic function by reading off its roots and taking the arithmetic average of them to obtain the x-coordinate of the quadratic function, and then substituting that value into the function."

Step-by-step explanation:

Because of the symmetry of quadratics (which is the case here because we have two factors of degree 1, so we are dealing with a <em>polynomial</em> of degree 2, which is a fancy way of saying that something is a quadratic), the x-coordinate of the extremum (a fancy way of saying maximum or minimum) is the (arithmetic) average of the two roots.

In the factored form of a quadratic function, we can immediately read the roots: 3 and 7. Another way to see that is to solve (x-3)(x-7)=0, which gives x-3=0 \vee x-7=0 (the 'V' stands for 'or'). We can take the average of the two roots to get the x-coordinate of the minimum point of the graph (which, in this case, is x=\frac{3+7}{2} = \frac{10}{2} = 5).

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cestrela7 [59]

Answer:

r = 33

s = 18

Step-by-step explanation:

Given expression is \frac{6+\sqrt{27}}{4-\sqrt{3}}.

Multiply numerator and denominator with the conjugate of (4 - √3).  

\frac{(6+\sqrt{27})(4+\sqrt{3})}{(4-\sqrt{3})(4+\sqrt{3})}

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