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MissTica
3 years ago
7

In the diagram below, which distance represents the distance from point Jto

Mathematics
1 answer:
sesenic [268]3 years ago
6 0
Have you gotten the answer yet?
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What is a inequality that has a solution of x&gt;8<br><br> PLEASE ANSWER. WILL MARK BRAINIELST.
MArishka [77]
The result can be shown in multiple forms.
Inequality Form:

X > 8
Interval Notation:

,
(8,∞)
4 0
3 years ago
Find an explicit rule for the nth term of the sequence.<br><br> -1, -5, -25, -125, ...
KonstantinChe [14]

Answer:

-(5^N)

Step-by-step explanation:

The sequence is a negated 5 to the N power

ex.) -(5^0) = -1

-(5^1) = -5

-(5^2) = -25

-(5^3) =125

8 0
3 years ago
11 1/4 divided by 3/4
Evgesh-ka [11]
45/4 * 4/3 = 45/3 is the answer
8 0
3 years ago
Read 2 more answers
Find the approximate volume of this prism.
dexar [7]

Answer:

61.57~~ 62

answer is 62

Step-by-step explanation:

V = B × H

B = a^2×sqrt(3)/4

6 0
4 years ago
May I have some help with these, please?
Nookie1986 [14]

Minimum = 18, Q₁ = 27.5, median = 39.5, Q₃ = 43, maximum = 49.

The five-number summary is a descriptive statistic that provides information on a series of observations. It consists of the following statistics:

1. Minimum: the smallest observation

2. First quartile  Q₁: the average of the values ​​below the median.

3. Medium  M: the average term.

4. third quartile  Q₃: the average of values ​​above the median.

5. Maximum: The largest observation.

The data represents the numbers of runs allowed by 8 college pitchers.

{18, 49, 38, 41, 33, 44, 42, 22}

The five-number summary is:

First, we have to sort the data from least to greatest.

{18, 22, 33, 38, 41, 42, 44, 49}

From the ordered data we can see that the minimum value is 18 and the maximum is 49.

The median is the middle term of the data set. In this case of an even number of terms, the median is the average of the terms located in the middle. So, the terms located in the middle if the data are in bold:

{18, 22, 33, 38, 41, 42, 44, 49}

Median= (38 + 41)/2 = 79/2 = 39.5

To calculate the first quartile Q₁, the values ​​below the median are {18, 22, 33, 38}. So, the median of this values is the first quartile Q₁:

{18, 22, 33, 38}

Q₁ = (22 + 33)/2 = 55/2 = 27.5

To calculate the third quartile  Q₃, the values ​​above the median are {41, 42, 44, 49}. So, the median of this values is the third quartile Q₃:

{41, 42, 44, 49}

Q₃ = (42 + 44)/2 = 86/2 = 43

8 0
3 years ago
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