Hi,
a line is define by the following equation : y = ax+b
where a is the slope, and b the value for x = 0
so you have : a*3 +b = 3 for the first point
a*(-5) +b = 4 for second point
so you have a system : 3a+b =3
-5a+b = 4
so : 3a+b -(-5a) -b = 3-4
3a+5a +b-b = -1
8a = -1
a = -1/8
then a = -1/8 so , in remplacing a by it's value in one equation , b is : 3(-1/8) +b = 3
-3/8 +b = 3
b = 3 +3/8
b = 24/8 +3/8
b = 27/8
let's check : 3 (-1/8) + 27/8 = -3/8 +27/8 = 24/8 = 3
first point is correct
-5( -1/8) + 27/8 = 5/8 +27/8 = 32/8 = 4
second point is correct
line is y = -1/8X +27/8
Answer:
ln 559872
Step-by-step explanation:
2 In 6 + 3 In 4 - 5 In (1/3) = ln 6² + ln 4³ - ln (⅓)⁵
= ln 36 + ln 64 - ln 1/243
= ln [(36×64)/(1/243)]
= ln 559872
We have that
<span>points A (-5, 6) and B (7, -1)
Part A)
find the distance
d=</span>√[(y2-y1)²+(x2-x1)²]-------> d=√[(-1-6)²+(7+5)²]----> d=√(49+144)
d=√193 units
Part B)
find the midpoint
ABx=(x1+x2)/2-----> (-5+7)/2-----> ABx=1
ABy=(y1+y2)/2-----> (-1+6)/2-----> ABy=2.5
the midpoint is (1,2.5)
Part C)
find the slope
m=(y2-y1)/(x2-x1)-----> m=(-1-6)/(7+5)--------> m=-7/12
the slope m=-7/12
