Please help! Will mark the brainliest!

If x2 + y2=6 , xy = 5 , then (X + y)2? <br><br><br><br>

VARVARA [1.3K]

Answer:

(x + y)² =16

Step-by-step explanation:

hello :

(x + y)² = x²+y²+2xy and : x²+y² = 6 xy = 5

(x + y)² = 6+2(5)

(x + y)² =16

3 0

2 years ago

WERE MY BISEXUAL KING AND QUEENS!!! :3

Soloha48 [4]

Answer:

sdf

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

HEELP please i dont under stand

DIA [1.3K]

The answer is A 3/10 because there is 3 blue marbles and all together there is 10

7 0

3 years ago

Read 2 more answers

On Planet Galactica, common units of distance are alpha, beta, and gamma. 4 gammas equal 5 betas. 2 betas equal 3 alphas. How ma

Ghella [55]

Answer:

1 gamma = 15/8 alphas

Step-by-step explanation:

so we start by finding out what 1 gamma and 1 beta equals.

we know 4 gammas = 5 betas so if we divide by four on both sides we get:

1 gamma = 5/4 betas. we can apply that same procedure to 2 betas = 3 alphas and get 1 beta = 3/2 alphas

we know that 1 gamma = 5/4 betas and 1 beta = 3/2 alphas so how many alphas = 5/4 betas? using a proportion of ((3/2)/1) = ((x)/(5/4)) we can find that 5/4 betas = 15/8 alphas

therefore we know 1 gamma = 15/8 alphas or 1 and 7/8 alphas

3 0

2 years ago

Suppose that a local TV station conducts a survey of a random sample of 120 registered voters in order to predict the winner of

forsale [732]

Answer:

a) The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b) The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

Step-by-step explanation:

Question a:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

Sample of 120 registered voters in order to predict the winner of a local election. The Democrat candidate was favored by 62 of the respondents.

So 120 - 62 = 58 favored the Republican candidate, so:

$n = 120, \pi = \frac{58}{120} = 0.4833$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a p-value of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 - 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.3658$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 + 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.6001$

The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b. If a candidate needs a simple majority of the votes to win the election, can the Republican candidate be confident of victory? Justify your response with an appropriate statistical argument.

The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

8 0

3 years ago