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Svetllana [295]

2 years ago

7

or a 10 point quiz, the professor recorded the following scores for 8 students: 7, 8, 3, 9, 10, 6, 8, 5 What is the Mean for thi

s set of scores

1 answer:

pav-90 [236]2 years ago

3 0

Since know mean is the same as average, we have the expression:

(7+8+3+9+10+6+5)/8 = 48/8 = 6

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Simplify sin^2y/sec^2 y−1 to a single trigonometric function

liubo4ka [24]

Answer:

$\frac{ { \sin}^{2} y}{ { \sec}^{2}y - 1 } = { \cos }^{2} y$

Step-by-step explanation:

We know that ${ \tan }^{2} y = { \sec }^{2} y - 1$

Also , ${ \tan}^{2} y = \frac{ { \sin }^{2} y}{ { \cos }^{2}y }$

So ,

$\frac{ { \sin }^{2}y }{ { \sec }^{2}y - 1 } = \frac{ { \sin}^{2} y}{ { \tan }^{2} y} = \frac{ { \sin }^{2}y }{ \frac{ { \sin}^{2} y}{ { \cos}^{2}y } } = { \cos }^{2} y$

6 0

3 years ago

Rewrite the expression with rational exponents as a radical expression.

SpyIntel [72]

I think it’s the last one but I’m not sure. Let me know if you get it right.

3 0

2 years ago

I really need help with b I have already done a

marishachu [46]

Answer:

Step-by-step explanation:

In the first pattern, there were 6 sticks

In the second pattern, there were 10 sticks.

In the third pattern, there were 14 sticks.

Based on the pattern, we see that each time, 4 more sticks are added and that the initial amount of stick is 6.

Thus: the equation for how many sticks there would be in pattern n is:

# of sticks in pattern n = 6 + 4n

Hope that helps!

3 0

3 years ago

What is the value of x in the equation 2(x-3)+9=3(x+1)+x?

Sergio039 [100]

Answer:

Step-by-step explanation:

5 0

3 years ago

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Write the standard form of the quadratic function whose graph is a parabola with the given vertex and that passes through the gi

maks197457 [2]

Answer:

The formula for this quadratic function is x*2 +6x+13

Step-by-step explanation:

If we have the vertex and one point of a parabola it is possible to find the quadratic function by the use of this

y= a (x-h)*2 + K

Quadratic function looks like this

y= ax*2 + bx + c

So let's find the a

y= a (x-h)*2 + K where

y is 13, x is 0, h is -3 and K is 4

13= a (0-(-3))*2 +4

13=9a +4

9=9a

9/9=a

1=a

The quadratic function will be

y= 1(x+3)*2 + 4

Let's get the classic form

(x+3)*2 = (x+3)(x+3)

(x*2+3x+3x+9)

x*2 +6x+13

f(0) = 13

6 0

4 years ago

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