Answer:
a. First order.
b. 
c. 
d. ![[A]=0.111M](https://tex.z-dn.net/?f=%5BA%5D%3D0.111M)
Explanation:
Hello.
a. In this case since the slope is in s⁻¹ we can infer that the lineal form of the rate law is:
![ln[A]=-kt+ln[A]_0](https://tex.z-dn.net/?f=ln%5BA%5D%3D-kt%2Bln%5BA%5D_0)
Which is also:

It means that the reaction is first-order as slope equals the negative of the rate constant which also has units of first-oder reaction.
b. Since the slope is −3.7 x 10−3 s−1 the rate constant is:

c. For first-order reactions, the half-life is:

d. In this case, since the integrated first-order rate law is:
![[A]=[A]_0exp(-kt)](https://tex.z-dn.net/?f=%5BA%5D%3D%5BA%5D_0exp%28-kt%29)
The concentration once 220 seconds have passed is:
![[A]=0.250Mexp(-3.7x10^{-3}s^{-1}*220s)\\\\](https://tex.z-dn.net/?f=%5BA%5D%3D0.250Mexp%28-3.7x10%5E%7B-3%7Ds%5E%7B-1%7D%2A220s%29%5C%5C%5C%5C)
![[A]=0.111M](https://tex.z-dn.net/?f=%5BA%5D%3D0.111M)
Regards.
Answer:
13.94moles of Na₂O
Explanation:
The balanced reaction expression is given as:
4Na + O₂ → 2Na₂O
Given parameters:
Number of moles of O₂ = 6.97moles
Unknown:
Number of moles of Na₂O
Solution:
To solve this problem;
1 mole of O₂ will produce 2 moles of Na₂O ;
6.97 moles of O₂ will produce 6.97 x 2 = 13.94moles of Na₂O
Three ways (out of the many) are:
Change of temperature
Color change
Formation of gas
Hope this helps!! (:
Answer:
its actually experimental this time
Explanation:
sorry bout the last one i just wanna help:(